In a network diagram, Activity A has a duration of 5 days, Activity B has 3 days, and Activity C has 4 days. Activity A and B can start simultaneously, but Activity C cannot start until both A and B are complete. What is the critical path duration?
Activity C depends on both A and B, so its earliest start is the longer of the two parallel paths: A finishes at day 5, B at day 3. Adding C's 4 days gives 9 days, the critical path duration. The A-C sequence governs, not B-C.
Why this answer
The critical path is the longest sequence of dependent activities. Activities A (5 days) and B (3 days) run in parallel, so the earliest they can both finish is day 5 (when A completes). Activity C (4 days) starts after both finish, so it runs from day 5 to day 9.
Thus the total project duration is 5 + 4 = 9 days, making D the correct answer.
Exam trap
PK0-005 often tests whether candidates mistakenly add all durations sequentially or incorrectly use the shorter parallel activity, forgetting that the critical path is the longest path through the network.
How to eliminate wrong answers
Option A (7 days) is wrong because it incorrectly adds B's duration to C (3+4) while ignoring that A must also finish, and A is longer than B. Option B (8 days) is wrong because it likely averages or misadds the parallel durations, perhaps assuming A and B finish at different times but not accounting for the full 5-day wait. Option C (12 days) is wrong because it simply sums all three durations (5+3+4) as if they were sequential, ignoring that A and B can run in parallel.