PK0-005 Project Life Cycle Practice Question
A project has three activities: Activity A (5 days), Activity B (7 days), Activity C (4 days). Activity B depends on A. Activity C depends on B. What is the total float for Activity B?
⚠ Common exam trap
PK0-005 often tests whether candidates confuse activity duration with float — the trap is picking the duration of B (7) or another activity instead of computing LS − ES.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
0 days
Activity B is on the critical path: A (5) → B (7) → C (4) = 16 days total, and B has no slack because any delay to B delays C and the project. Total float is calculated as Late Start − Early Start (or Late Finish − Early Finish); for B, both are equal, giving 0 days of float.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
5 days
Why it's wrong here
Activity B has zero total float because it is on the critical path; five days is Activity A's duration. The figure tempts because A is B's predecessor, suggesting its length somehow transfers as slack, but float is calculated from path timing, not inherited from preceding activities.
- ✗
7 days
Why it's wrong here
Activity B lies on the critical path, giving zero total float; seven days is simply B's own duration. The value tempts because duration is the most visible number attached to the activity, but float measures scheduling slack between earliest and latest dates, not how long the task takes.
- ✗
4 days
Why it's wrong here
Activity B sits on the critical path, so its total float is zero; four days is Activity C's duration, not slack. The figure tempts because C is the shortest activity, inviting the assumption that short duration implies spare time, yet float derives from path length, not individual duration.
- ✓
0 days
Why this is correct
The chain A then B then C gives a single critical path of 5+7+4 days, so no slack exists anywhere along it. Activity B sits on that critical path, meaning any delay slips the project; its total float is therefore zero days.
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Written and reviewed by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
Last reviewed September 2026 · checked against the official CompTIA exam blueprint
This PK0-005 practice question is part of Courseiva's free CompTIA certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the PK0-005 exam.