An ACL entry reads: access-list 25 permit 192.168.8.0 0.0.0.15 Which address range does this statement match?
The wildcard mask 0.0.0.15 (binary 00000000.00000000.00000000.00001111) fixes the first 28 bits and allows the last 4 bits of the fourth octet to vary. Because the network portion is 192.168.8.0, these 4 variable bits produce every address from .0 (00000000) to .15 (00001111), inclusive. Thus this ACL entry matches exactly the 16 addresses 192.168.8.0 through 192.168.8.15.
Why this answer
A wildcard of 0.0.0.15 means the last 4 bits can vary, which corresponds to a block size of 16 addresses. Starting at 192.168.8.0, the range is 192.168.8.0 through 192.168.8.15.
Exam trap
Be careful not to confuse the block size determined by the wildcard mask with a full subnet or miscalculate the starting address.
Why the other options are wrong
This range uses a wildcard mask of 0.0.0.7, not 0.0.0.15.
When would these options actually be correct?
If the question were modified to read 'access-list 25 permit 192.168.8.0 0.0.0.31', then option B would be correct, as it would match the entire range from 192.168.8.0 to 192.168.8.31.
This option would be correct if the question specified that the ACL was intended to match only the addresses within the range of 192.168.8.8 to 192.168.8.15, perhaps in a context where a specific subnet mask was applied to limit the range.
In a different question, if the ACL entry specified 'access-list 25 permit 192.168.8.15 0.0.0.0', then option D would be correct, as it would permit only the host address 192.168.8.15.
Why candidates pick the wrong answer
Students often confuse wildcard masks with subnet masks, thinking that 0.0.0.15 corresponds to a /27 subnet (255.255.255.224) which has 32 addresses, but wildcard masks are the inverse of subnet masks.
A test-taker might mistakenly think the wildcard mask indicates the starting point or that the range is centered around the given address, leading to an incorrect starting offset.
Students may see the last octet .15 in the wildcard mask and incorrectly assume it matches only the host with that specific value, confusing the wildcard mask with a host address.