A host is configured with IP address 192.168.50.94/27. Which subnet contains that host?
Answer choices
Why each option matters
Good practice is not just finding the correct option. The wrong answers often show the exact trap the exam wants you to fall into.
Distractor review
192.168.50.32/27
This is wrong because that subnet ends at .63.
Best answer
192.168.50.64/27
This is correct because .94 falls within the .64 through .95 block.
Distractor review
192.168.50.96/27
This is wrong because that block begins above the host address.
Distractor review
192.168.50.0/27
This is wrong because that block covers only .0 through .31.
Common exam trap
Common exam trap: answer the scenario, not the keyword
A frequent exam trap is assuming the subnet containing the host IP address is the closest subnet boundary numerically, such as choosing 192.168.50.96/27 for the IP 192.168.50.94 simply because 94 is near 96. This mistake happens when candidates forget to calculate the subnet block size from the prefix length and instead rely on intuition or partial knowledge. The /27 prefix means each subnet contains 32 addresses, so the correct subnet must be a multiple of 32 starting from zero. Misidentifying the subnet leads to incorrect network design or troubleshooting errors.
Technical deep dive
How to think about this question
Subnetting is a fundamental concept in IP networking that divides a larger network into smaller, manageable subnetworks. A subnet mask, such as /27, defines how many bits are used for the network portion and how many for the host portion of an IP address. In the case of a /27 mask, 27 bits are allocated to the network, leaving 5 bits for host addresses, which results in 32 IP addresses per subnet (2^5 = 32). These addresses include network, usable host, and broadcast addresses. To determine which subnet contains a specific host IP address, you calculate the block size by subtracting the prefix length from 32 and raising 2 to that power. For /27, the block size is 32 addresses. Starting from 0, subnets increment by 32 in the last octet: 0–31, 32–63, 64–95, 96–127, etc. Since the host IP 192.168.50.94 falls within the 64–95 range, it belongs to the 192.168.50.64/27 subnet. A common exam trap is selecting a subnet boundary close to the host IP without calculating the block size properly. For example, choosing 192.168.50.96/27 because 94 is near 96 is incorrect since 96–127 is the next subnet block. Understanding how to convert prefix length to block size and then mapping the host IP to the correct subnet range is critical for accurate subnetting in Cisco exams and real-world networking.
KKey Concepts to Remember
- A /27 subnet mask allocates 27 bits to the network portion and leaves 5 bits for host addresses, resulting in 32 IP addresses per subnet.
- The block size for a subnet is calculated as 2 to the power of (32 minus the prefix length), which defines the range of IP addresses in each subnet.
- Subnet ranges start at zero and increment by the block size in the last octet, such as 0–31, 32–63, 64–95, and so on for a /27 mask.
- To determine the subnet containing a host IP, compare the host's last octet to the subnet ranges derived from the block size calculation.
- Choosing a subnet based solely on proximity to the host IP without calculating block size leads to incorrect subnet identification.
- Cisco devices use subnet masks to determine network boundaries and route traffic correctly within and between subnets.
- Understanding subnetting block sizes and ranges is essential for configuring IP addressing schemes and troubleshooting network issues.
- The network address of a subnet is always the first IP in the block, and the broadcast address is the last IP in the block.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
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More questions from this exam
Keep practising from the same exam bank, or move into a focused topic page if this question exposed a weak area.
Question 1
A router learns the same prefix from both OSPF and EIGRP. Which route is installed by default?
Question 2
A router shows this output: R1#show ip ospf neighbor Neighbor ID Pri State Dead Time Address Interface 10.1.1.2 1 FULL/DR 00:00:34 192.168.12.2 GigabitEthernet0/0 10.1.1.3 1 2WAY/DROTHER 00:00:39 192.168.12.3 GigabitEthernet0/0 Which statement is correct?
Question 3
What is the OSPF metric called?
Question 4
A non-root switch has two uplinks toward the root bridge. One path has a lower total STP cost than the other. What role will the lower-cost uplink have?
Question 5
A router interface applies this ACL inbound: 10 deny tcp any any eq 80 20 permit ip any any A user reports that web browsing to a server by IP address fails, but ping works. Which statement best explains the behavior?
Question 6
A router learns route 198.51.100.0/24 from OSPF with AD 110 and also has a static route to the same prefix configured with AD 150. Which route is installed?
FAQ
Questions learners often ask
What does this 200-301 question test?
A /27 subnet mask allocates 27 bits to the network portion and leaves 5 bits for host addresses, resulting in 32 IP addresses per subnet.
What is the correct answer to this question?
The correct answer is: 192.168.50.64/27 — A /27 subnet has a block size of 32. In simple terms, the fourth-octet ranges are 0–31, 32–63, 64–95, 96–127, and so on. Because 94 falls inside the 64–95 range, the network address for the host’s subnet is 192.168.50.64/27. This kind of question tests whether you can move from prefix length to block size and then place the host inside the correct interval. The most common mistake is choosing a nearby boundary like 96 or 32 without calculating the actual block that contains the address.
What should I do if I get this 200-301 question wrong?
Then try more questions from the same exam bank and focus on understanding why the wrong options are tempting.
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