This 200-301 practice question tests your understanding of network infrastructure and connectivity. Match the stated requirement to the specific cloud service, access model, or configuration option — many options are valid in isolation but not for this scenario. A key principle to apply: a /28 subnet mask creates subnets with 16 IP addresses, including network, broadcast, and usable host addresses.. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A host address is 192.168.14.222/28. Which address is the broadcast address of its subnet?
192.168.14.207
Why wrong: This is wrong because .207 is the broadcast of the previous /28 block.
192.168.14.223
This is correct because .222 belongs to the 208-223 /28 subnet.
192.168.14.208
Why wrong: This is wrong because .208 is the network address of the block.
192.168.14.224
Why wrong: This is wrong because .224 starts the next /28 subnet.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
192.168.14.223
A /28 subnet has a block size of 16. In practical terms, the fourth-octet blocks are 0-15, 16-31, and so on. Because 222 falls within the 208-223 block, the broadcast address is the last address in that block: 192.168.14.223. This is a subnet-boundary question that depends on identifying the correct /28 block before choosing the broadcast address.
Key principle: A /28 subnet mask creates subnets with 16 IP addresses, including network, broadcast, and usable host addresses.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
192.168.14.207
Why it's wrong here
This is wrong because .207 is the broadcast of the previous /28 block.
When this WOULD be correct
If the question asked for the broadcast address of a different subnet, such as 192.168.14.192/28, then option A (192.168.14.207) would be correct, as it would be the broadcast address for that specific subnet.
192.168.14.223
Why this is correct
This is correct because .222 belongs to the 208-223 /28 subnet.
Related concept
A /28 subnet mask creates subnets with 16 IP addresses, including network, broadcast, and usable host addresses.
192.168.14.208
Why it's wrong here
This is wrong because .208 is the network address of the block.
When this WOULD be correct
If the question specified a subnet mask of /29 instead of /28, and the host address was 192.168.14.208, then option C would be the correct answer as the broadcast address would be 192.168.14.215 for that subnet.
192.168.14.224
Why it's wrong here
This is wrong because .224 starts the next /28 subnet.
When this WOULD be correct
If the question specified a subnet mask of /27 instead of /28, the address 192.168.14.224 would be the broadcast address for the subnet 192.168.14.192/27, which encompasses the range from 192.168.14.192 to 192.168.14.224.
Option-by-option analysis
Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The 200-301 exam frequently reuses these exact scenarios with slightly different constraints.
Why this is correct
This is correct because .222 belongs to the 208-223 /28 subnet.
Why this is wrong here
192.168.14.207 is the broadcast address of the previous /28 subnet (192.168.14.192/28), not the subnet containing 192.168.14.222.
★ When this WOULD be the correct answer
If the question asked for the broadcast address of a different subnet, such as 192.168.14.192/28, then option A (192.168.14.207) would be correct, as it would be the broadcast address for that specific subnet.
Why candidates choose this
A student might miscalculate the subnet boundaries or confuse the broadcast address with that of an adjacent subnet.
Why this is wrong here
192.168.14.208 is the network address (subnet ID) of the /28 subnet containing .222, not the broadcast address.
★ When this WOULD be the correct answer
If the question specified a subnet mask of /29 instead of /28, and the host address was 192.168.14.208, then option C would be the correct answer as the broadcast address would be 192.168.14.215 for that subnet.
Why candidates choose this
Students often confuse the network address with the broadcast address, especially when they know the subnet starts at .208.
Why this is wrong here
192.168.14.224 is the network address of the next /28 subnet (192.168.14.224/28), not the broadcast of the current subnet.
★ When this WOULD be the correct answer
If the question specified a subnet mask of /27 instead of /28, the address 192.168.14.224 would be the broadcast address for the subnet 192.168.14.192/27, which encompasses the range from 192.168.14.192 to 192.168.14.224.
Why candidates choose this
A student might incorrectly add the block size (16) to the host address or think the broadcast is the next network address.
Analysis generated from the official 200-301blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”
Common exam traps
Be careful not to confuse the broadcast address with the network address of the next subnet or a host address within the subnet.
Detailed technical explanation
Subnetting is a fundamental concept in IP networking that divides a larger network into smaller, manageable subnetworks. A /28 subnet mask corresponds to 255.255.255.240, which means the last octet has 4 bits for host addressing, allowing 16 IP addresses per subnet. These 16 addresses include one network address, 14 usable host addresses, and one broadcast address. The block size of 16 is derived from 256 minus the subnet mask's last octet value (240), which defines the range of IP addresses within each subnet. To determine the broadcast address for a given IP with a /28 mask, you first identify the subnet block it belongs to by calculating multiples of 16 in the last octet. For 192.168.14.222, the subnet block is 208 to 223 because 222 falls within this range. The broadcast address is always the highest address in the subnet block, which is 192.168.14.223 in this case. This process ensures correct identification of network boundaries and broadcast addresses, which is critical for proper IP routing and communication. A common exam trap is confusing the broadcast address with the network address or the broadcast address of an adjacent subnet. For example, 192.168.14.207 is the broadcast for the previous subnet block (192.168.14.192/28), not the one containing 192.168.14.222. Understanding the block size and correctly calculating subnet boundaries prevents this mistake. In practical networking, accurate broadcast address identification ensures that broadcast traffic is correctly contained within its subnet, avoiding unnecessary network congestion and routing errors.
Key takeaway
A /28 subnet mask creates subnets with 16 IP addresses, including network, broadcast, and usable host addresses.
Real-world example
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
What to study next
Review a /28 subnet mask creates subnets with 16 IP addresses, including network, broadcast, and usable host addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
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FAQ
Network Infrastructure and Connectivity — This question tests Network Infrastructure and Connectivity — A /28 subnet mask creates subnets with 16 IP addresses, including network, broadcast, and usable host addresses..
The correct answer is: 192.168.14.223 — A /28 subnet has a block size of 16. In practical terms, the fourth-octet blocks are 0-15, 16-31, and so on. Because 222 falls within the 208-223 block, the broadcast address is the last address in that block: 192.168.14.223. This is a subnet-boundary question that depends on identifying the correct /28 block before choosing the broadcast address.
Review a /28 subnet mask creates subnets with 16 IP addresses, including network, broadcast, and usable host addresses., then practise related 200-301 questions on the same topic to reinforce the concept.
A /28 subnet mask creates subnets with 16 IP addresses, including network, broadcast, and usable host addresses.
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Last reviewed: May 17, 2026
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