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PK0-005 Practice Question: Refer to the exhibit

Exhibit

Refer to the exhibit.

```
[Project Schedule - Critical Path]
Task A (5d) -> Task C (3d) -> Task E (4d) -> Task G (2d)
Task B (6d) -> Task D (4d) -> Task F (5d) -> Task H (3d)
Dependencies: Task C depends on A and B; Task D depends on B; Task E depends on C; Task F depends on D; Task G depends on E; Task H depends on F. All durations in days. No other dependencies.
```

Refer to the exhibit. What is the total float for Task D?

⚠ Common exam trap

CompTIA often tests the concept that tasks on the critical path have zero total float, and the trap here is that candidates may miscalculate float by using incorrect early/late dates from the diagram or confuse total float with free float, leading to picking a non-zero value.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

0 days

Task D has a total float of 0 days because it lies on the critical path. In the network diagram, its early start (ES) equals its late start (LS), and its early finish (EF) equals its late finish (LF), indicating no schedule flexibility. This means any delay in Task D would directly extend the project duration. The critical path includes Task D, so total float is zero.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • ✗

    4 days

    Why it's wrong here

    Incorrect calculation.

  • ✗

    3 days

    Why it's wrong here

    Incorrect calculation.

  • ✗

    2 days

    Why it's wrong here

    Incorrect calculation.

  • ✓

    0 days

    Why this is correct

    Task D is on critical path.

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

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