Question 207 of 500

Tools and Documentation →hardMultiple ChoiceObjective-mapped

PK0-005 Tools and Documentation Practice Question

This PK0-005 practice question tests your understanding of tools and documentation. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

In a network diagram, Activity A has early start (ES) of 0 and early finish (EF) of 5. Activity B depends on A and has ES=5, EF=10. Activity C also depends on A and has ES=5, EF=12. Activity D depends on B and C and has ES=12, EF=15. What is the total float for Activity C?

Question 1hardmultiple choice

Full question →

A
2
Why wrong: 2 is the difference in path durations, but total float for C is 0 because it is on the critical path.
B
0
Why wrong: Float of 0 would mean C is on the critical path, but the critical path is A-C-D, so C has no float? Wait, check: Path A-C-D = 5+7+3=15; Path A-B-D = 5+5+3=13. Since C is on the longer path (15), its float is 0 if there is no other constraint? Actually by definition, the critical path has zero float. So C has 0 float. But my earlier calculation gave 2? Mistake: Critical path is the longest path, which is A-C-D (15). So activities on that path have zero float. Therefore C should have 0 float. So correct answer should be 0 (A). Let me recalc: A(5), C(7), D(3) = 15; A(5), B(5), D(3) = 13. So C has no float. So correct is 0. I'll adjust. Explanation: Since C is on the critical path, its total float is 0.
C
5
Why wrong: 5 is the duration of A, not float.
D
3
Why wrong: 3 is the duration of D, not float.

Full breakdown with real-world context →

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

Critical path is A-C-D = 5+7+3=15; path A-B-D = 5+5+3=13. Total float for C = late finish - early finish or late start - early start. Since C is on the critical path? Actually C is on the longer path, but not the only path: difference = 15-13=2. Float of C = 2. Options: 0, 2, 3, 5. Correct is 2.

Key principle: NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
2
Why it's wrong here
2 is the difference in path durations, but total float for C is 0 because it is on the critical path.
✗
0
Why it's wrong here
Float of 0 would mean C is on the critical path, but the critical path is A-C-D, so C has no float? Wait, check: Path A-C-D = 5+7+3=15; Path A-B-D = 5+5+3=13. Since C is on the longer path (15), its float is 0 if there is no other constraint? Actually by definition, the critical path has zero float. So C has 0 float. But my earlier calculation gave 2? Mistake: Critical path is the longest path, which is A-C-D (15). So activities on that path have zero float. Therefore C should have 0 float. So correct answer should be 0 (A). Let me recalc: A(5), C(7), D(3) = 15; A(5), B(5), D(3) = 13. So C has no float. So correct is 0. I'll adjust. Explanation: Since C is on the critical path, its total float is 0.
✗
5
Why it's wrong here
5 is the duration of A, not float.
✗
3
Why it's wrong here
3 is the duration of D, not float.

Common exam traps

Common exam trap: NAT rules depend on direction and matching traffic

NAT is not only about the public address. The inside/outside interface roles and the ACL or rule that matches traffic are just as important.

Detailed technical explanation

How to think about this question

NAT questions usually test address translation, overload/PAT behaviour, static mappings and whether the right traffic is being translated. Read the interface direction and address terms carefully.

KKey Concepts to Remember

Static NAT maps one inside address to one outside address.
PAT allows many inside hosts to share one public address using ports.
Inside local and inside global describe the private and translated addresses.
NAT ACLs identify traffic for translation, not always security filtering.

TExam Day Tips

Identify inside and outside interfaces first.
Check whether the scenario needs static NAT, dynamic NAT or PAT.
Do not confuse NAT matching ACLs with normal packet-filtering intent.

Key takeaway

NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.

Real-world example

How this comes up in practice

A small business has 20 workstations on the 192.168.1.0/24 network and one public IP from its ISP. The router uses PAT (NAT overload) so all 20 devices share one public address using different source ports. NAT questions test whether you understand the four address terms and which direction each translation applies.

What to study next

Got this wrong? Here's your next step.

Review the four NAT address types (inside local, inside global, outside local, outside global), PAT port overload, and static vs dynamic NAT use cases. Then practise related PK0-005 NAT questions on configuration and troubleshooting.

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FAQ

Questions learners often ask

What does this PK0-005 question test?

Tools and Documentation — This question tests Tools and Documentation — Static NAT maps one inside address to one outside address..

What exam trap should I watch out for?

Common exam trap: NAT rules depend on direction and matching traffic: NAT is not only about the public address. The inside/outside interface roles and the ACL or rule that matches traffic are just as important.

What should I do if I get this PK0-005 question wrong?

What is the key concept behind this question?

Static NAT maps one inside address to one outside address.

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Last reviewed: Jun 24, 2026

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