The answer is 11 days. This is correct because the total duration of a project is determined by the longest path through the network diagram, known as the critical path, which dictates the earliest possible completion date. In this scenario, both path A → B → D and path A → C → D take 11 days, as activity D cannot start until both B and C finish, with C ending later on day 9, pushing D to finish on day 11. On the CompTIA Project+ PK0-005 exam, this tests your ability to calculate project duration from critical path by identifying dependencies and summing durations along the longest sequence, a core skill for schedule management questions. A common trap is to simply add all activity durations without accounting for parallel tasks or the dependency that forces a later start. Remember the memory tip: “The critical path is the longest line, not the sum of all time.”
PK0-005 Project Management Concepts Practice Question
This PK0-005 practice question tests your understanding of project management concepts. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Exhibit
Task | Duration | Dependencies | Start | Finish
A | 5d | None | Day 1 | Day 5
B | 3d | A | Day 6 | Day 8
C | 4d | A | Day 6 | Day 9
D | 2d | B,C | Day 10| Day 11
Refer to the exhibit. What is the total duration of the project?
Task | Duration | Dependencies | Start | Finish
A | 5d | None | Day 1 | Day 5
B | 3d | A | Day 6 | Day 8
C | 4d | A | Day 6 | Day 9
D | 2d | B,C | Day 10| Day 11
A
9 days
Why wrong: 9 days is less than the critical path.
B
8 days
Why wrong: 8 days is not possible given the task durations.
C
14 days
Why wrong: This would be if durations were summed without considering dependencies.
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
11 days
The critical path is A → B → D or A → C → D. A takes 5 days (days 1-5). B takes 3 days (days 6-8), C takes 4 days (days 6-9). D depends on both B and C, so it starts after the latest finish (day 9) and finishes on day 11. Thus total duration is 11 days. Option A is correct.
Key principle: NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
9 days
Why it's wrong here
9 days is less than the critical path.
✗
8 days
Why it's wrong here
8 days is not possible given the task durations.
✗
14 days
Why it's wrong here
This would be if durations were summed without considering dependencies.
✓
11 days
Why this is correct
Project starts day 1, ends day 11, total 11 days.
Related concept
Static NAT maps one inside address to one outside address.
Common exam traps
Common exam trap: NAT rules depend on direction and matching traffic
NAT is not only about the public address. The inside/outside interface roles and the ACL or rule that matches traffic are just as important.
Detailed technical explanation
How to think about this question
NAT questions usually test address translation, overload/PAT behaviour, static mappings and whether the right traffic is being translated. Read the interface direction and address terms carefully.
KKey Concepts to Remember
Static NAT maps one inside address to one outside address.
PAT allows many inside hosts to share one public address using ports.
Inside local and inside global describe the private and translated addresses.
NAT ACLs identify traffic for translation, not always security filtering.
TExam Day Tips
→Identify inside and outside interfaces first.
→Check whether the scenario needs static NAT, dynamic NAT or PAT.
→Do not confuse NAT matching ACLs with normal packet-filtering intent.
Key takeaway
NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.
Real-world example
How this comes up in practice
A small business has 20 workstations on the 192.168.1.0/24 network and one public IP from its ISP. The router uses PAT (NAT overload) so all 20 devices share one public address using different source ports. NAT questions test whether you understand the four address terms and which direction each translation applies.
What to study next
Got this wrong? Here's your next step.
Review the four NAT address types (inside local, inside global, outside local, outside global), PAT port overload, and static vs dynamic NAT use cases. Then practise related PK0-005 NAT questions on configuration and troubleshooting.
Project Management Concepts — This question tests Project Management Concepts — Static NAT maps one inside address to one outside address..
What is the correct answer to this question?
The correct answer is: 11 days — The critical path is A → B → D or A → C → D. A takes 5 days (days 1-5). B takes 3 days (days 6-8), C takes 4 days (days 6-9). D depends on both B and C, so it starts after the latest finish (day 9) and finishes on day 11. Thus total duration is 11 days. Option A is correct.
What should I do if I get this PK0-005 question wrong?
Review the four NAT address types (inside local, inside global, outside local, outside global), PAT port overload, and static vs dynamic NAT use cases. Then practise related PK0-005 NAT questions on configuration and troubleshooting.
What is the key concept behind this question?
Static NAT maps one inside address to one outside address.
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Question Discussion
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