A data analyst needs to summarize customer satisfaction scores. The data contains a few extremely low scores that skew the distribution. Which measure of central tendency is most appropriate?
Extremely low scores pull the mean downward, so it no longer represents typical satisfaction. The median resists this skew because it depends only on positional rank, not magnitude, satisfying the need to summarise a distribution distorted by outliers.
Why this answer
The median is the most appropriate measure of central tendency when data contains extreme outliers, such as the very low customer satisfaction scores described. Unlike the mean, the median is resistant to skew because it depends only on the middle value(s) of the sorted dataset, not on the magnitude of extreme values. This makes it the standard choice for summarizing ordinal or skewed interval/ratio data in data analysis.
Exam trap
The trap here is that candidates often default to the mean as the 'average' without considering outlier impact, but CompTIA Data+ tests the understanding that the mean is non-robust and the median is the correct choice for skewed data in the Analyzing and Modeling domain.
How to eliminate wrong answers
Option A (Range) is wrong because it is a measure of dispersion (the difference between the maximum and minimum values), not a measure of central tendency, and it is heavily influenced by outliers. Option B (Mode) is wrong because it identifies the most frequently occurring score, which may not represent the center of the distribution and can be misleading when outliers are present but not frequent. Option D (Mean) is wrong because it is sensitive to extreme values; the few extremely low scores will pull the arithmetic mean downward, misrepresenting the typical customer satisfaction experience.