A network engineer runs the following command to troubleshoot an EIGRP issue: R1# show ip eigrp topology 10.1.1.0/24 IP-EIGRP (AS 100): Topology entry for 10.1.1.0/24 State: Passive, Query origin flag: 1, 1 Successor(s), FD is 131072 Routing Descriptor Blocks: 10.1.2.2 (GigabitEthernet0/0), from 10.1.2.2, Send flag: 0x0 Composite metric: (131072/130816), Route is Internal Vector metric: Minimum bandwidth is 10000 Kbit Total delay is 100 microseconds Reliability is 255/255 Load is 1/255 Minimum MTU is 1500 Hop count is 1 10.1.3.3 (GigabitEthernet0/1), from 10.1.3.3, Send flag: 0x0 Composite metric: (131328/131072), Route is Internal Vector metric: Minimum bandwidth is 10000 Kbit Total delay is 200 microseconds Reliability is 255/255 Load is 1/255 Minimum MTU is 1500 Hop count is 2 What does this output indicate?
Correct. Only the first path is a successor and is installed. The second path is not a feasible successor (RD == FD), so it is not immediately usable; it is only a backup that requires a query to become active.
Why this answer
The output shows two paths for 10.1.1.0/24. The first path has a composite metric of (131072/130816), making the feasible distance (FD) 131072. The second path has a composite metric of (131328/131072), where the reported distance (131072) equals the FD.
For a path to be a feasible successor, the reported distance must be strictly less than the FD. Since the second path's reported distance equals the FD, it does not satisfy the feasibility condition and is not a feasible successor. Therefore, only the first path is a successor and is installed in the routing table.
The second path is stored in the topology table but is not used unless a query process occurs. Thus, option A is correct.
Exam trap
Candidates often misread the topology table and assume that any path with a reported distance less than or equal to the FD is a feasible successor. However, the feasibility condition requires a strict inequality (RD < FD). Here, the second path's RD equals the FD, so it is not a feasible successor.
How to eliminate wrong answers
Option A is wrong because the second path is not a backup; it is a feasible successor that is maintained in the topology table but not used unless the successor fails. Option C is wrong because both paths are not installed in the routing table; only the successor is installed, and unequal-cost load balancing requires the 'variance' command, which is not configured here. Option D is wrong because the route state is 'Passive', not 'Active'; an Active state would indicate a query is in progress, but the output clearly shows 'State: Passive'.