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1Z0-829 · topic practice

Controlling Program Flow practice questions

Practise RAM questions covering identification, installation, speeds, dual-channel, and troubleshooting for the 1Z0-829 exam.

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Reviewed byJohnson Ajibi· MSc IT Security

16 questionsDomain: Controlling Program Flow

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What the exam tests

What to know about Controlling Program Flow

RAM tests your ability to identify, install, and troubleshoot memory types, speeds, and configurations for PCs.

Identifying DDR3 vs DDR4 vs DDR5 physical and electrical differences

Matching RAM speed (MHz) to motherboard and CPU support

Calculating total memory capacity from module size and slots

Troubleshooting common RAM errors like beep codes and blue screens

Why learners struggle

Why Controlling Program Flow questions are commonly missed

RAM questions are commonly missed because learners confuse physical form factors (DIMM vs SO-DIMM) and fail to distinguish between memory speed (MHz) and latency (CL).

·DIMM vs SO-DIMM — desktop vs laptop form factor confusion
·DDR3 vs DDR4 vs DDR5 — notch position and voltage differences
·MHz vs CL — speed vs latency trade-offs in performance
·Single-channel vs dual-channel — bandwidth impact misconception
·ECC vs non-ECC — error correction support in servers vs desktops
·32-bit vs 64-bit — maximum addressable RAM limit

Watch out for

Common Controlling Program Flow exam traps

▸Confusing DDR3 and DDR4 notch positions and voltage requirements
▸Assuming dual-channel requires identical size modules only
▸Mixing ECC and non-ECC RAM in a single system
▸Forgetting that 32-bit OS limits usable RAM to 4 GB

Practice set

Controlling Program Flow questions

16 questions · select your answer, then reveal the explanation

Question 1mediummultiple choice

Read the full Controlling Program Flow explanation →

A developer writes code to iterate over a list of strings and print each element. The code uses an enhanced for loop. Which statement is true about the enhanced for loop?

Trap 1: It can only be used with arrays.

It can also be used with collections that implement Iterable.

Trap 2: It requires an explicit counter variable.

The enhanced for loop hides the counter variable.

Trap 3: It allows removing elements from the collection during iteration…

Removing elements during iteration with enhanced for loop causes ConcurrentModificationException.

Study all Controlling Program Flow common traps →

A
It can be used with arrays and any object that implements Iterable.
The enhanced for loop works on arrays and Iterable objects.
B
It can only be used with arrays.
Why wrong: It can also be used with collections that implement Iterable.
C
It requires an explicit counter variable.
Why wrong: The enhanced for loop hides the counter variable.
D
It allows removing elements from the collection during iteration without ConcurrentModificationException.
Why wrong: Removing elements during iteration with enhanced for loop causes ConcurrentModificationException.

Full breakdown with real-world context →

Question 2easymultiple choice

Read the full Controlling Program Flow explanation →

Given the code snippet:

int x = 10;
if (x > 5) {

System.out.print("A");

} else if (x > 7) {

System.out.print("B");

} else {

System.out.print("C");

What is the output?

Trap 1: C

The else is skipped.

Trap 2: ABC

Only one branch executes.

Trap 3: B

The else if is skipped.

Study all Controlling Program Flow common traps →

A
C
Why wrong: The else is skipped.
B
ABC
Why wrong: Only one branch executes.
C
A
The first condition is true.
D
B
Why wrong: The else if is skipped.

Full breakdown with real-world context →

Question 3hardmultiple choice

Read the full Controlling Program Flow explanation →

A method contains a try-with-resources statement that uses two resources: a FileInputStream and a BufferedInputStream. The FileInputStream constructor throws a FileNotFoundException. Which statement about resource closing is true?

Trap 1: The BufferedInputStream is closed if it was successfully created,…

The BufferedInputStream is declared second and would not be opened if the first failed.

Trap 2: Both resources are closed even if the FileInputStream constructor…

Only successfully opened resources are closed.

Trap 3: The programmer must explicitly close the resources in a finally…

Try-with-resources closes resources automatically.

Study all Controlling Program Flow common traps →

A
The BufferedInputStream is closed if it was successfully created, but the FileInputStream is not.
Why wrong: The BufferedInputStream is declared second and would not be opened if the first failed.
B
Both resources are closed even if the FileInputStream constructor throws an exception.
Why wrong: Only successfully opened resources are closed.
C
No resources are closed because the FileInputStream constructor failed before any resource was opened.
The first constructor threw an exception, so no resource was opened.
D
The programmer must explicitly close the resources in a finally block.
Why wrong: Try-with-resources closes resources automatically.

Full breakdown with real-world context →

Question 4mediummulti select

Read the full Controlling Program Flow explanation →

Which TWO statements are true about the switch statement in Java?

Trap 1: Case values can be variables that are not final.

Case values must be compile-time constants.

Trap 2: It requires a default case.

Default is optional.

Trap 3: Each case must have a unique code block.

Multiple case labels can share a code block.

Study all Controlling Program Flow common traps →

A
Case values can be variables that are not final.
Why wrong: Case values must be compile-time constants.
B
It can be used with String objects.
String is allowed in switch since Java 7.
C
It requires a default case.
Why wrong: Default is optional.
D
It can be used as an expression that yields a value.
Switch expressions were introduced in Java 14.
E
Each case must have a unique code block.
Why wrong: Multiple case labels can share a code block.

Full breakdown with real-world context →

Question 5hardmulti select

Read the full Controlling Program Flow explanation →

Which THREE statements are true about loops in Java?

Trap 1: A while loop always executes at least once.

While loop may execute zero times.

Trap 2: A do-while loop may execute zero times if the condition is false.

Do-while executes at least once.

Study all Controlling Program Flow common traps →

A
The break statement can be used to exit a loop prematurely.
Break exits the loop.
B
A while loop always executes at least once.
Why wrong: While loop may execute zero times.
C
The continue statement skips the rest of the current iteration.
Continue jumps to the next iteration.
D
A do-while loop may execute zero times if the condition is false.
Why wrong: Do-while executes at least once.
E
A for loop can have multiple loop variables.
Multiple variables can be declared and updated.

Full breakdown with real-world context →

Question 6hardmultiple choice

Read the full Controlling Program Flow explanation →

You are developing a high-frequency trading application that processes a stream of market data ticks. Each tick is represented by a Tick object with fields: long timestamp, String symbol, double price, int volume. Ticks arrive in real-time and must be processed in order. A bug is reported: the application occasionally processes a tick out of order, causing incorrect trade decisions. The processing logic uses a while loop to read from a blocking queue and process each tick. The code is:

BlockingQueue<Tick> queue = new LinkedBlockingQueue<>();

while (true) {

Tick tick = queue.take(); process(tick);

After investigation, you find that the queue is fed by multiple producer threads that sometimes reorder ticks due to network delays. Which course of action best ensures ticks are processed in the correct chronological order without sacrificing throughput?

Trap 1: Use a SynchronousQueue and have producers wait for the consumer to…

SynchronousQueue does not buffer; it would not help reordering.

Trap 2: After taking from the queue, sort a batch of ticks before…

Does not prevent reordering and adds complexity.

Trap 3: Add a delay before processing to allow out-of-order ticks to arrive.

Introduces latency and does not guarantee order.

Study all Controlling Program Flow common traps →

A
Use a SynchronousQueue and have producers wait for the consumer to acknowledge.
Why wrong: SynchronousQueue does not buffer; it would not help reordering.
B
After taking from the queue, sort a batch of ticks before processing.
Why wrong: Does not prevent reordering and adds complexity.
C
Replace LinkedBlockingQueue with a PriorityBlockingQueue that orders by timestamp.
PriorityBlockingQueue maintains ordering by timestamp.
D
Add a delay before processing to allow out-of-order ticks to arrive.
Why wrong: Introduces latency and does not guarantee order.

Full breakdown with real-world context →

Question 7easymultiple choice

Read the full Controlling Program Flow explanation →

Which loop construct guarantees that the body executes at least once?

Trap 1: for loop

May execute zero times.

Trap 2: enhanced for loop

May execute zero times.

Trap 3: while loop

May execute zero times.

Study all Controlling Program Flow common traps →

A
for loop
Why wrong: May execute zero times.
B
enhanced for loop
Why wrong: May execute zero times.
C
while loop
Why wrong: May execute zero times.
D
do-while loop
Condition checked after body.

Full breakdown with real-world context →

Question 8hardmultiple choice

Read the full Controlling Program Flow explanation →

What is the output of the program?

Exhibit

Refer to the exhibit.

public class LoopTest {
    public static void main(String[] args) {
        outer:
        for (int i = 0; i < 3; i++) {
            for (int j = 0; j < 3; j++) {
                if (i + j > 3) {
                    break outer;
                }
                System.out.print(i + j + " ");
            }
        }
    }
}

Trap 1: 0 1 2 1 2 3 2 3 4

4 is not printed because break outer occurs before printing.

Trap 2: 0 1 2 1 2 3 2 3 4 5

Includes extra numbers.

Trap 3: 0 1 2 1 2 3 2 3 3 4

Extra numbers from inner loop.

Study all Controlling Program Flow common traps →

A
0 1 2 1 2 3 2 3 4
Why wrong: 4 is not printed because break outer occurs before printing.
B
0 1 2 1 2 3 2 3
Correct sequence as per execution.
C
0 1 2 1 2 3 2 3 4 5
Why wrong: Includes extra numbers.
D
0 1 2 1 2 3 2 3 3 4
Why wrong: Extra numbers from inner loop.

Full breakdown with real-world context →

Question 9mediummulti select

Read the full Controlling Program Flow explanation →

Which TWO statements about the switch statement in Java are correct?

Trap 1: Case values can be runtime expressions.

Case values must be compile-time constants.

Trap 2: A break statement is mandatory after each case block.

Break is optional; fall-through occurs without it.

Trap 3: Case labels can be variables if they are final and assigned a…

They must be compile-time constants, but final variables are allowed only if initialized with constant expressions.

Study all Controlling Program Flow common traps →

A
The default case can be placed anywhere within the switch block.
Default can be at any position.
B
Case values can be runtime expressions.
Why wrong: Case values must be compile-time constants.
C
A break statement is mandatory after each case block.
Why wrong: Break is optional; fall-through occurs without it.
D
Case labels can be variables if they are final and assigned a constant expression.
Why wrong: They must be compile-time constants, but final variables are allowed only if initialized with constant expressions.
E
The switch statement can be used with int, char, String, and enum types.
These are valid types for switch.

Full breakdown with real-world context →

Question 10easymultiple choice

Read the full Controlling Program Flow explanation →

A Java application processes a list of orders. Each order has a status: NEW, PROCESSING, SHIPPED, or DELIVERED. The code must print a message based on the status: - If NEW: "Order received" - If PROCESSING: "Order in progress" - If SHIPPED: "Order shipped" - If DELIVERED: "Order delivered" - For any other status: "Unknown status"

The developer writes the following code using a switch expression:

String message = switch (status) { case NEW -> "Order received"; case PROCESSING -> "Order in progress"; case SHIPPED -> "Order shipped"; case DELIVERED -> "Order delivered"; default -> "Unknown status";

};

System.out.println(message);

What is the correct course of action to ensure the code compiles and runs correctly?

Trap 1: Add a default branch to handle any other status.

There is already a default branch.

Trap 2: Use if-else if statements because switch cannot be used with enum…

Switch can be used with enums.

Trap 3: Change the switch expression to a switch statement because switch…

Switch expressions can yield values.

Study all Controlling Program Flow common traps →

A
Add a default branch to handle any other status.
Why wrong: There is already a default branch.
B
Use if-else if statements because switch cannot be used with enum types.
Why wrong: Switch can be used with enums.
C
No change needed; the code compiles and runs as expected.
The code is syntactically correct and covers all cases.
D
Change the switch expression to a switch statement because switch expressions cannot yield values.
Why wrong: Switch expressions can yield values.

Full breakdown with real-world context →

Question 11easymulti select

Read the full Controlling Program Flow explanation →

Which TWO statements about the switch statement in Java are true?

Trap 1: A switch statement can be used as an expression in all cases.

Switch expressions (with ->) can assign a value, but traditional switch with colon cannot.

Trap 2: The switch expression can be of type long.

long is not allowed; switch supports byte, short, char, int, String, and enum types.

Trap 3: The case values can be variables.

Case values must be compile-time constants (literals or final variables initialized with constants).

Study all Controlling Program Flow common traps →

A
A break statement is optional.
Without break, execution falls through to the next case.
B
A switch statement can be used as an expression in all cases.
Why wrong: Switch expressions (with ->) can assign a value, but traditional switch with colon cannot.
C
The switch expression can be of type long.
Why wrong: long is not allowed; switch supports byte, short, char, int, String, and enum types.
D
The switch expression can be of type String.
String is allowed as a switch expression since Java 7.
E
The case values can be variables.
Why wrong: Case values must be compile-time constants (literals or final variables initialized with constants).

Full breakdown with real-world context →

Question 12hardmultiple choice

Read the full NAT/PAT explanation →

A Java developer is writing a batch processing application that reads records from a database and processes them. The processing must continue even if some records cause exceptions (e.g., data conversion errors). However, the application must log each failed record and its error, then continue with the next record. The developer uses a for loop to iterate over a list of records. Inside the loop, a try-catch block wraps the processing logic. After implementing, the developer notices that when an exception occurs, the loop terminates prematurely instead of continuing. The code structure is:

List<Record> records = fetchRecords();

for (Record rec : records) {

try { process(rec);

} catch (Exception e) {

log.error("Failed to process: " + rec.getId(), e);

}
}

What is the most likely reason for the premature termination?

Trap 1: The records list contains null elements, causing a…

NullPointerException is an Exception, so it would be caught.

Trap 2: The log.error() method itself throws an unchecked exception that is…

If log.error throws an unchecked exception, it would propagate out of the catch block and terminate the loop, but this is less likely than an Error from process().

Trap 3: The try-catch block is incorrectly placed inside the for loop,…

The try-catch inside the loop is correct for continuing after exceptions; it does not cause termination.

Study all Controlling Program Flow common traps →

A
The records list contains null elements, causing a NullPointerException that is not caught.
Why wrong: NullPointerException is an Exception, so it would be caught.
B
The process() method throws an Error instead of an Exception.
Errors are not caught by catch(Exception), causing the loop to terminate.
C
The log.error() method itself throws an unchecked exception that is not caught.
Why wrong: If log.error throws an unchecked exception, it would propagate out of the catch block and terminate the loop, but this is less likely than an Error from process().
D
The try-catch block is incorrectly placed inside the for loop, causing the loop to break on any exception.
Why wrong: The try-catch inside the loop is correct for continuing after exceptions; it does not cause termination.

Full breakdown with real-world context →

Question 13mediumdrag order

Read the full Controlling Program Flow explanation →

Order the steps to properly handle resources using try-with-resources in Java.

Drag steps to the numbered slots on the right, or tap a step then tap a slot.

Steps

Order

1Step 1

2Step 2

3Step 3

4Step 4

5Step 5

Question 14mediumdrag order

Read the full Controlling Program Flow explanation →

Order the steps to handle checked exceptions in a method that throws IOException.

Drag steps to the numbered slots on the right, or tap a step then tap a slot.

Steps

Order

1Step 1

2Step 2

3Step 3

4Step 4

5Step 5

Question 15mediummatching

Read the full Controlling Program Flow explanation →

Match each Java module directive to its description.

Drag a concept onto its matching description — or click a concept then click the description.

Concepts

Matches

Makes a package accessible to other modules

Specifies a dependency on another module

Allows reflective access to a package at runtime

Declares a service implementation

Specifies a service interface consumed by the module

Question 16mediummatching

Read the full Controlling Program Flow explanation →

Match each I/O stream class to its description.

Drag a concept onto its matching description — or click a concept then click the description.

Concepts

Matches

Reads text from a character-input stream, buffering characters

Reads raw bytes from a file

Writes primitive types and Java objects to an OutputStream

Prints formatted representations of objects to a text-output stream

Reads primitive Java data types from an underlying input stream

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Frequently asked questions

What does the 1Z0-829 exam test about Controlling Program Flow?: RAM tests your ability to identify, install, and troubleshoot memory types, speeds, and configurations for PCs.
How should I use these practice questions?: Select your answer before revealing the explanation. Then read why each option is right or wrong — this active recall approach builds retention far faster than re-reading notes.
Can I practise just Controlling Program Flow questions in a focused session?: Yes — the session launcher on this page draws every question from the Controlling Program Flow domain. Use a 10-question session first to gauge your baseline, then move to 20 or 30 once the weak spots are clear.
Where can I practise other 1Z0-829 topics?: Use the topic links above to move to related areas, or go back to the 1Z0-829 question bank to see all topics.
Are these real exam questions or dumps?: These are original practice questions written to test the same concepts the 1Z0-829 exam covers. They are not copied from any real exam or dump site.

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All 1Z0-829 questions Controlling Program Flow domain overview 1Z0-829 exam guide

Exam traps to avoid

▸Confusing DDR3 and DDR4 notch positions and voltage requirements
▸Assuming dual-channel requires identical size modules only
▸Mixing ECC and non-ECC RAM in a single system
▸Forgetting that 32-bit OS limits usable RAM to 4 GB

Controlling Program Flow practice questions

What to know about Controlling Program Flow

Why Controlling Program Flow questions are commonly missed

Common Controlling Program Flow exam traps

Controlling Program Flow questions

A developer writes code to iterate over a list of strings and print each element. The code uses an enhanced for loop. Which statement is true about the enhanced for loop?

A method contains a try-with-resources statement that uses two resources: a FileInputStream and a BufferedInputStream. The FileInputStream constructor throws a FileNotFoundException. Which statement about resource closing is true?

Which TWO statements are true about the switch statement in Java?

Which THREE statements are true about loops in Java?

Which loop construct guarantees that the body executes at least once?

What is the output of the program?

Exhibit

Which TWO statements about the switch statement in Java are correct?

Which TWO statements about the switch statement in Java are true?

Order the steps to properly handle resources using try-with-resources in Java.

Order the steps to handle checked exceptions in a method that throws IOException.

Match each Java module directive to its description.

Match each I/O stream class to its description.

Track your progress over time

Start a Controlling Program Flow only practice session

Related 1Z0-829 topic practice pages

Handling Date, Time, Text, Numeric and Boolean Values practice questions