- A
The default case can be placed anywhere within the switch block.
Default can be at any position.
- B
Case values can be runtime expressions.
Why wrong: Case values must be compile-time constants.
- C
A break statement is mandatory after each case block.
Why wrong: Break is optional; fall-through occurs without it.
- D
Case labels can be variables if they are final and assigned a constant expression.
Why wrong: They must be compile-time constants, but final variables are allowed only if initialized with constant expressions.
- E
The switch statement can be used with int, char, String, and enum types.
These are valid types for switch.
1Z0-829 Controlling Program Flow Practice Question
This 1Z0-829 practice question tests your understanding of controlling program flow. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Which TWO statements about the switch statement in Java are correct?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
The default case can be placed anywhere within the switch block.
Option A is correct because the Java Language Specification allows the default case to appear anywhere within the switch block, not just at the end. The switch statement evaluates the expression and jumps to the matching case label; if no match is found, it jumps to the default label regardless of its position. This flexibility is important for code organization and readability.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
The default case can be placed anywhere within the switch block.
Why this is correct
Default can be at any position.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
Case values can be runtime expressions.
Why it's wrong here
Case values must be compile-time constants.
- ✗
A break statement is mandatory after each case block.
Why it's wrong here
Break is optional; fall-through occurs without it.
- ✗
Case labels can be variables if they are final and assigned a constant expression.
Why it's wrong here
They must be compile-time constants, but final variables are allowed only if initialized with constant expressions.
- ✓
The switch statement can be used with int, char, String, and enum types.
Why this is correct
These are valid types for switch.
Related concept
Read the scenario before looking for a memorised answer.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates often assume the default case must be last, or that break is always required, or that any final variable can be used as a case label, when in fact only compile-time constant expressions are allowed.
Detailed technical explanation
How to think about this question
Under the hood, the Java compiler optimizes switch statements using either a tableswitch or lookupswitch bytecode instruction, which requires case values to be compile-time constants. For enum types, the compiler uses an ordinal-based lookup, and for String, it uses the hashCode() of the constant to generate an integer switch. A common subtlety is that fall-through can be intentional, such as when multiple cases share the same code block, but forgetting a break is a frequent source of bugs.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
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FAQ
Questions learners often ask
What does this 1Z0-829 question test?
Controlling Program Flow — This question tests Controlling Program Flow — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: The default case can be placed anywhere within the switch block. — Option A is correct because the Java Language Specification allows the default case to appear anywhere within the switch block, not just at the end. The switch statement evaluates the expression and jumps to the matching case label; if no match is found, it jumps to the default label regardless of its position. This flexibility is important for code organization and readability.
What should I do if I get this 1Z0-829 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Last reviewed: Jun 11, 2026
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