Controlling Program Flow →mediumMultiple ChoiceObjective-mapped

1Z0-829 Controlling Program Flow Practice Question

Exhibit

Refer to the exhibit.

```
int[] numbers = {1, 2, 3, 4, 5};
int sum = 0;
for (int i = 0; i < numbers.length; i++) {
    if (numbers[i] % 2 == 0) {
        continue;
    }
    sum += numbers[i];
}
System.out.println(sum);
```

What is the output?

```java

int x = 10;

do { System.out.print(x);

} while (x-- > 10);

```

⚠ Common exam trap

The trap here is that candidates often forget that the post-decrement operator uses the original value in the condition before decrementing, leading them to think the first printed value is 10 instead of 9.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

10 because in the missing code, the loop condition likely uses pre-decrement or the print statement occurs before the decrement, so the first value printed is the initial value of x, which is 10. The post-decrement trap described in the current explanation does not apply.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
9
Why it's wrong here
This is incorrect because if the print occurs before decrement, the first output is 10, not 9.
✗
15
Why it's wrong here
This value is not produced by any typical loop with x starting at 10.
✓
10
Why this is correct
This is correct because the missing code outputs 10 as the first and only value.
✗
6
Why it's wrong here
This value does not match the expected output from the described code.

Go deeper

1Z0-829 Controlling Program Flow Practice Question

Exhibit

Why each option matters

Option-by-option breakdown

Related to this question