- A
192.168.1.0
Why wrong: This would be the network address if the subnet were /24, but with /26 it is not correct.
- B
192.168.1.128
Correct: 130 is in the range 128-191, so the network address is 192.168.1.128.
- C
192.168.1.192
Why wrong: This network address covers 192-255, which does not include 130.
- D
192.168.1.64
Why wrong: This network address covers 64-127, which does not include 130.
Question 95 of 520
N10-009 Network address calculation Practice Question
This N10-009 practice question tests your understanding of networking concepts. This is a configuration task: choose the command set that satisfies every stated requirement. Small differences — like 'secret' vs 'password' or 'transport input ssh' vs 'all' — change whether the answer is correct. A key principle to apply: network address calculation. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A device is configured with IP address 192.168.1.130 and subnet mask 255.255.255.192. What is the network address of this device?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
192.168.1.128
The network address is found by performing a bitwise AND between the IP address 192.168.1.130 and the subnet mask 255.255.255.192. The mask 255.255.255.192 has a prefix length of /26, meaning the first 26 bits are the network portion. 192.168.1.130 in binary is 11000000.10101000.00000001.10000010, and the mask is 11111111.11111111.11111111.11000000; the AND yields 11000000.10101000.00000001.10000000, which is 192.168.1.128.
Key principle: Network address calculation
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
192.168.1.0
Why it's wrong here
This would be the network address if the subnet were /24, but with /26 it is not correct.
When this WOULD be correct
This would be correct if the subnet mask were 255.255.255.0 (or /24), as the network address for 192.168.1.130 with a /24 mask is 192.168.1.0.
- ✓
192.168.1.128
Why this is correct
Correct: 130 is in the range 128-191, so the network address is 192.168.1.128.
Related concept
Network address calculation
- ✗
192.168.1.192
Why it's wrong here
This network address covers 192-255, which does not include 130.
When this WOULD be correct
This option would be correct if the IP address were 192.168.1.194 with the same subnet mask 255.255.255.192, as that IP falls in the 192.168.1.192/26 subnet.
- ✗
192.168.1.64
Why it's wrong here
This network address covers 64-127, which does not include 130.
When this WOULD be correct
This option would be correct if the subnet mask were 255.255.255.192 and the IP address were in the range 192.168.1.65 to 192.168.1.126, such as 192.168.1.100, making the network address 192.168.1.64.
Option-by-option analysis
Why each answer is right or wrong
Understanding why wrong answers are wrong — and when they would be correct — is what separates a 750 score from a 900. The N10-009 exam frequently reuses these exact scenarios with slightly different constraints.
✓192.168.1.128Correct answer▾
Why this is correct
Correct: 130 is in the range 128-191, so the network address is 192.168.1.128.
✗192.168.1.0Wrong answer — click to see why▾
Why this is wrong here
The network address is obtained by ANDing the IP address with the subnet mask. For 192.168.1.130 and 255.255.255.192, the network address is 192.168.1.128, not 192.168.1.0.
★ When this WOULD be the correct answer
This would be correct if the subnet mask were 255.255.255.0 (or /24), as the network address for 192.168.1.130 with a /24 mask is 192.168.1.0.
Why candidates choose this
Candidates often default to the classful network address (Class C /24) without considering the subnet mask, assuming 192.168.1.0 is always the network address.
✗192.168.1.192Wrong answer — click to see why▾
Why this is wrong here
With subnet mask 255.255.255.192 (/26), the network address is found by ANDing the IP with the mask: 192.168.1.130 AND 255.255.255.192 = 192.168.1.128. Option C (192.168.1.192) is the next subnet's network address, not the one containing this IP.
★ When this WOULD be the correct answer
This option would be correct if the IP address were 192.168.1.194 with the same subnet mask 255.255.255.192, as that IP falls in the 192.168.1.192/26 subnet.
Why candidates choose this
Candidates may mistakenly think the network address is the subnet's broadcast address or confuse the subnet boundaries, especially if they misapply the mask or miscalculate the increment (64 vs 128).
✗192.168.1.64Wrong answer — click to see why▾
Why this is wrong here
With subnet mask 255.255.255.192 (/26), the network address is calculated by performing a bitwise AND between the IP address and the mask. 192.168.1.130 AND 255.255.255.192 yields 192.168.1.128, not 192.168.1.64.
★ When this WOULD be the correct answer
This option would be correct if the subnet mask were 255.255.255.192 and the IP address were in the range 192.168.1.65 to 192.168.1.126, such as 192.168.1.100, making the network address 192.168.1.64.
Why candidates choose this
Candidates may mistakenly think the network address is the first octet boundary (e.g., 192.168.1.0) or miscalculate the subnet increment, confusing the 64-bit boundary with the 128-bit boundary.
Analysis generated from the official N10-009blueprint and verified against question context. The “when correct” sections are what AI assistants cite when candidates ask “what’s the difference between these options?”
Common exam traps
Common exam trap: answer the scenario, not the keyword
The N10-009 exam often tests the confusion between the network address and the broadcast address, especially when the IP address falls near the boundary of a subnet, leading candidates to mistakenly pick the broadcast address (192.168.1.192) or the default classful network (192.168.1.0).
Detailed technical explanation
How to think about this question
The subnet mask 255.255.255.192 (/26) creates subnets with a block size of 64 addresses. The network address always has the host bits set to 0, so for the subnet starting at 192.168.1.128, the valid host range is 192.168.1.129–192.168.1.190, with 192.168.1.191 as the broadcast address. In real-world routing, the network address is used in routing tables (e.g., 'ip route 192.168.1.128 255.255.255.192') to summarize the subnet.
KKey Concepts to Remember
- Network address calculation
- Subnet mask /26 (255.255.255.192)
- Block size (increment)
- Network vs. broadcast address
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Network address calculation
Real-world example
How this comes up in practice
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
Visual reference
What to study next
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Review network address calculation, then practise related N10-009 questions on the same topic to reinforce the concept.
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FAQ
Questions learners often ask
What does this N10-009 question test?
Networking Concepts — This question tests Networking Concepts — Network address calculation.
What is the correct answer to this question?
The correct answer is: 192.168.1.128 — The network address is found by performing a bitwise AND between the IP address 192.168.1.130 and the subnet mask 255.255.255.192. The mask 255.255.255.192 has a prefix length of /26, meaning the first 26 bits are the network portion. 192.168.1.130 in binary is 11000000.10101000.00000001.10000010, and the mask is 11111111.11111111.11111111.11000000; the AND yields 11000000.10101000.00000001.10000000, which is 192.168.1.128.
What should I do if I get this N10-009 question wrong?
Review network address calculation, then practise related N10-009 questions on the same topic to reinforce the concept.
What is the key concept behind this question?
Network address calculation
About these practice questions
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Last reviewed: Jun 11, 2026
This N10-009 practice question is part of Courseiva's free CompTIA certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the N10-009 exam.
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