Quick Answer
The network address is 192.168.1.128. This is correct because to find the network address from an IP and subnet mask, you perform a bitwise AND operation between the IP address and the subnet mask; the mask’s binary 1s preserve the network portion of the IP, while its 0s zero out the host bits. For 192.168.1.130 with a 255.255.255.192 mask (a /26 prefix), the last octet in binary is 10000010 ANDed with 11000000, yielding 10000000, which is 128. On the CompTIA Network+ N10-009 exam, this skill tests your understanding of subnetting fundamentals and the ability to distinguish the network address from the broadcast or first usable host address. A common trap is confusing the network address with the IP itself, especially when the host bits are not all zeros. Remember the memory tip: “AND the IP with the mask, and the network address is what you get back.”
This N10-009 practice question tests your understanding of networking concepts. This is a configuration task: choose the command set that satisfies every stated requirement. Small differences — like 'secret' vs 'password' or 'transport input ssh' vs 'all' — change whether the answer is correct. A key principle to apply: a subnet mask defines the network and host portions of an IP address.. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A device is configured with IP address 192.168.1.130 and subnet mask 255.255.255.192. What is the network address of this device?
192.168.1.0
Why wrong: This would be the network address if the subnet were /24, but with /26 it is not correct.
192.168.1.128
Correct: 130 is in the range 128-191, so the network address is 192.168.1.128.
192.168.1.192
Why wrong: This network address covers 192-255, which does not include 130.
192.168.1.64
Why wrong: This network address covers 64-127, which does not include 130.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
192.168.1.128
The network address is found by performing a bitwise AND between the IP address 192.168.1.130 and the subnet mask 255.255.255.192. The mask 255.255.255.192 has a prefix length of /26, meaning the first 26 bits are the network portion. 192.168.1.130 in binary is 11000000.10101000.00000001.10000010, and the mask is 11111111.11111111.11111111.11000000; the AND yields 11000000.10101000.00000001.10000000, which is 192.168.1.128.
Key principle: A subnet mask defines the network and host portions of an IP address.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
192.168.1.0
Why it's wrong here
This would be the network address if the subnet were /24, but with /26 it is not correct.
192.168.1.128
Why this is correct
Correct: 130 is in the range 128-191, so the network address is 192.168.1.128.
Related concept
A subnet mask defines the network and host portions of an IP address.
192.168.1.192
Why it's wrong here
This network address covers 192-255, which does not include 130.
192.168.1.64
Why it's wrong here
This network address covers 64-127, which does not include 130.
Common exam traps
Cisco often tests the confusion between the network address and the broadcast address, especially when the IP address falls near the boundary of a subnet, leading candidates to mistakenly pick the broadcast address (192.168.1.192) or the default classful network (192.168.1.0).
Detailed technical explanation
The subnet mask 255.255.255.192 (/26) creates subnets with a block size of 64 addresses. The network address always has the host bits set to 0, so for the subnet starting at 192.168.1.128, the valid host range is 192.168.1.129–192.168.1.190, with 192.168.1.191 as the broadcast address. In real-world routing, the network address is used in routing tables (e.g., 'ip route 192.168.1.128 255.255.255.192') to summarize the subnet.
Key takeaway
A subnet mask defines the network and host portions of an IP address.
Real-world example
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
What to study next
Review a subnet mask defines the network and host portions of an IP address., then practise related N10-009 questions on the same topic to reinforce the concept.
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FAQ
Networking Concepts — This question tests Networking Concepts — A subnet mask defines the network and host portions of an IP address..
The correct answer is: 192.168.1.128 — The network address is found by performing a bitwise AND between the IP address 192.168.1.130 and the subnet mask 255.255.255.192. The mask 255.255.255.192 has a prefix length of /26, meaning the first 26 bits are the network portion. 192.168.1.130 in binary is 11000000.10101000.00000001.10000010, and the mask is 11111111.11111111.11111111.11000000; the AND yields 11000000.10101000.00000001.10000000, which is 192.168.1.128.
Review a subnet mask defines the network and host portions of an IP address., then practise related N10-009 questions on the same topic to reinforce the concept.
A subnet mask defines the network and host portions of an IP address.
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Last reviewed: Jun 11, 2026
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