Question 508 of 509

Quick Answer

The correct answer is that Instant.parse() returns an Instant representing 2023-12-31T23:59:59Z with an added nanosecond. This happens because the java.time.Instant class does not support a true 60th second; instead, it follows the ISO-8601 convention of handling a leap second by converting it to the last valid second of the minute (23:59:59) and then adding one nanosecond to account for the extra second. On the Oracle Certified Professional Java SE 17 Developer 1Z0-829 exam, this question tests your understanding of how the Java Time API resolves edge cases in date-time parsing, often appearing as a trick where candidates mistakenly expect an exception or a direct 60th second. The common trap is assuming Instant can store a leap second natively, but it always normalizes to a fractional adjustment. Memory tip: think “59 plus a nanosecond” — the leap second is just a tiny extra tick, not a full second on the clock.

1Z0-829 Practice Question: Handling Date, Time, Text, Numeric and Boolean Values

This 1Z0-829 practice question tests your understanding of handling date, time, text, numeric and boolean values. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

A developer needs to parse the string "2023-12-31T23:59:60Z" (a leap second) into a java.time.Instant. Which statement is true?

Question 1hardmultiple choice
Full question →

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

It returns an Instant representing 2023-12-31T23:59:59Z with an added nanosecond.

Option B is correct because java.time.Instant.parse() handles leap seconds by converting them to the last valid second of the minute (23:59:59) and then adding a nanosecond to account for the extra second. This behavior is specified by the ISO-8601 standard and the Java Time API, which does not support a true 60th second but represents it as an Instant with a fractional second adjustment.

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • It returns an Instant representing 2023-12-31T23:59:59Z, ignoring the leap second.

    Why it's wrong here

    Leap second is not ignored; it is handled.

  • It returns an Instant representing 2023-12-31T23:59:59Z with an added nanosecond.

    Why this is correct

    The 60th second is treated as the last nanosecond of the minute.

    Related concept

    Read the scenario before looking for a memorised answer.

  • It throws a DateTimeParseException because 60 seconds is invalid.

    Why it's wrong here

    Instant.parse handles leap seconds.

  • It returns null because the string is invalid.

    Why it's wrong here

    It returns an Instant, not null.

Common exam traps

Common exam trap: answer the scenario, not the keyword

The trap here is that candidates assume '60' seconds is always invalid and will cause an exception, but the Java Time API specifically accommodates leap seconds by converting them to the nearest valid nanosecond-adjusted Instant.

Detailed technical explanation

How to think about this question

Under the hood, java.time.format.DateTimeFormatter.ISO_INSTANT uses a resolver style that maps the second-of-minute value 60 to 59 and then adds 1 nanosecond (i.e., 59.000000001 seconds) to preserve the leap second's position in the UTC timeline. This aligns with the ITU-R TF.460-6 recommendation for leap seconds, ensuring that the Instant can be used in time arithmetic without breaking the continuous time scale. In real-world systems like financial trading or satellite navigation, this subtle handling prevents off-by-one errors when processing timestamps near leap second events.

KKey Concepts to Remember

  • Read the scenario before looking for a memorised answer.
  • Find the constraint that changes the correct option.
  • Eliminate answers that are true in general but not in this case.

TExam Day Tips

  • Watch for words such as best, first, most likely and least administrative effort.
  • Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.

What to study next

Got this wrong? Here's your next step.

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

Related practice questions

Related 1Z0-829 practice-question pages

Use these pages to review the topic behind this question. This is how one missed question becomes focused revision.

Practice this exam

Start a free 1Z0-829 practice session

Short sessions build daily habit. Longer sessions build exam-day stamina. Try a timed session to simulate real conditions.

FAQ

Questions learners often ask

What does this 1Z0-829 question test?

Handling Date, Time, Text, Numeric and Boolean Values — This question tests Handling Date, Time, Text, Numeric and Boolean Values — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: It returns an Instant representing 2023-12-31T23:59:59Z with an added nanosecond. — Option B is correct because java.time.Instant.parse() handles leap seconds by converting them to the last valid second of the minute (23:59:59) and then adding a nanosecond to account for the extra second. This behavior is specified by the ISO-8601 standard and the Java Time API, which does not support a true 60th second but represents it as an Instant with a fractional second adjustment.

What should I do if I get this 1Z0-829 question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

About these practice questions

Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →

How Courseiva writes practice questions · Editorial policy

Keep practising

More 1Z0-829 practice questions

Last reviewed: Jun 11, 2026

Question Discussion

Share a tip, memory trick, or ask about the reasoning behind this question. Do not post real exam questions, leaked content, braindumps, or copyrighted exam material. Comments are moderated and may be removed without notice.

Loading comments…

Sign in to join the discussion.

This 1Z0-829 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-829 exam.