- A
54321
The loop prints each number from 5 down to 1.
- B
Compilation error
Why wrong: The code is syntactically correct.
- C
543210
Why wrong: It does not print 0 because the condition is checked after decrement.
- D
5432
Why wrong: It also prints 1.
Question 199 of 519
Do-While Loop Execution Order — Entry-Controlled vs Exit-Controlled
This 1Z0-829 practice question tests your understanding of controlling program flow. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
What is the output of the following code? int i=5; do { System.out.print(i); i--; } while(i>0);
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
54321
The correct answer is A because the do-while loop executes the body first, printing the current value of i (5), then decrements i to 4. The loop continues while i > 0, so it prints 5, 4, 3, 2, 1, and stops when i becomes 0, as the condition i > 0 is false. This results in the output "54321".
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
54321
Why this is correct
The loop prints each number from 5 down to 1.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
Compilation error
Why it's wrong here
The code is syntactically correct.
- ✗
543210
Why it's wrong here
It does not print 0 because the condition is checked after decrement.
- ✗
5432
Why it's wrong here
It also prints 1.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates often mistakenly think the loop prints 0 because they overlook that the condition is checked after the body executes, and the loop exits when i becomes 0 without printing it.
Detailed technical explanation
How to think about this question
The do-while loop guarantees at least one execution of the loop body, unlike a while loop which may skip entirely if the condition is initially false. The post-decrement operator (i--) evaluates the current value of i before decrementing, which is why the printed values are 5,4,3,2,1. In real-world scenarios, this pattern is useful for menu-driven programs where the body must execute once before checking a sentinel value.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
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FAQ
Questions learners often ask
What does this 1Z0-829 question test?
Controlling Program Flow — This question tests Controlling Program Flow — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: 54321 — The correct answer is A because the do-while loop executes the body first, printing the current value of i (5), then decrements i to 4. The loop continues while i > 0, so it prints 5, 4, 3, 2, 1, and stops when i becomes 0, as the condition i > 0 is false. This results in the output "54321".
What should I do if I get this 1Z0-829 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
About these practice questions
Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
Same concept, more angles
1 more ways this is tested on 1Z0-829
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. Consider the following do-while loop: ```java int x = 10; do { x--; } while (x < 10); System.out.println(x); ``` What is printed?
medium- ✓ A.3
- B.The loop does not compile because x is not declared final.
- C.2
- D.1
Why A: The do-while loop executes the body first (x--), then checks the condition x < 10. After the first iteration, x becomes 9, and the condition (9 < 10) is true. As x continues to decrease, it will always be less than 10, so the condition remains true forever. This results in an infinite loop; the program never reaches the print statement. Therefore, no output is produced, and none of the options (3, 2, 1) are correct.
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Last reviewed: Jul 4, 2026
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