Question 296 of 509

Primitives, Strings and Operators →easyMultiple ChoiceObjective-mapped

1Z0-811 Primitives, Strings and Operators Practice Question

This 1Z0-811 practice question tests your understanding of primitives, strings and operators. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

A junior developer wrote the following code to compare two strings entered by a user: if (username == "admin") { grantAccess(); } else { denyAccess(); }. The code always denies access even when the user enters 'admin'. What is the most likely cause, and how should the code be fixed?

Clue words in this question

Noticing these words before you look at the options changes how you read each choice.

Clue: "most likely"
Why it matters: Probability qualifier — the question wants the most probable cause or outcome, not a guaranteed one. Eliminate low-probability options.
Clue: "always"
Why it matters: Absolute qualifier. An answer using 'always' is only correct if there are genuinely no exceptions — absolute statements are often wrong in networking.

A
The input string has leading or trailing spaces. Use username.trim().equals("admin") instead.
Why wrong: Possible but less likely; not the most likely cause.
B
The variable username is null, causing a NullPointerException that is caught and denied access. Add a null check.
Why wrong: NullPointerException would crash, not just deny.
C
The strings are compared using == which is case-sensitive. Use username.equalsIgnoreCase("admin") instead.
Why wrong: Case-sensitivity is not the issue.
D
The strings are compared using == which checks reference equality. Use username.equals("admin") instead.
equals compares content.

Full breakdown with real-world context →

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

The strings are compared using == which checks reference equality. Use username.equals("admin") instead.

Option D is correct because in Java, the == operator compares object references, not the actual content of strings. When comparing two String objects for logical equality, the .equals() method must be used. The code if (username == "admin") checks whether username and the string literal "admin" refer to the same memory location, which is false when username is obtained from user input (e.g., via Scanner or console), even if the characters are identical.

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
The input string has leading or trailing spaces. Use username.trim().equals("admin") instead.
Why it's wrong here
Possible but less likely; not the most likely cause.
✗
The variable username is null, causing a NullPointerException that is caught and denied access. Add a null check.
Why it's wrong here
NullPointerException would crash, not just deny.
✗
The strings are compared using == which is case-sensitive. Use username.equalsIgnoreCase("admin") instead.
Why it's wrong here
Case-sensitivity is not the issue.
✓
The strings are compared using == which checks reference equality. Use username.equals("admin") instead.
Why this is correct
equals compares content.
Clue confirmation
The clue words "most likely", "always" in the question point toward this answer.
Related concept
Read the scenario before looking for a memorised answer.

Common exam traps

Common exam trap: answer the scenario, not the keyword

Oracle Java Foundations exam often tests the distinction between reference equality (==) and value equality (.equals()) for String objects, and the trap here is that candidates may think the issue is case sensitivity or whitespace, when the fundamental problem is the use of the wrong comparison operator.

Detailed technical explanation

How to think about this question

In Java, string literals are interned and may reuse the same reference, so == can sometimes work for compile-time constants, but user input strings are created at runtime and always have distinct references. The .equals() method overrides Object.equals() to compare character sequences, and it is the standard way to test string equality. A common real-world scenario is validating user credentials, where using == can lead to authentication failures that are hard to debug.

KKey Concepts to Remember

Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.

TExam Day Tips

Watch for words such as best, first, most likely and least administrative effort.
Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A security administrator must allow nursing staff to reach a patient records server while blocking access from the guest Wi-Fi VLAN. After applying an extended ACL, traffic is still blocked from nursing workstations. The ACL was applied outbound instead of inbound on the wrong interface. Questions like this test ACL direction and placement rules.

What to study next

Got this wrong? Here's your next step.

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

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FAQ

Questions learners often ask

What does this 1Z0-811 question test?

Primitives, Strings and Operators — This question tests Primitives, Strings and Operators — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: The strings are compared using == which checks reference equality. Use username.equals("admin") instead. — Option D is correct because in Java, the == operator compares object references, not the actual content of strings. When comparing two String objects for logical equality, the .equals() method must be used. The code if (username == "admin") checks whether username and the string literal "admin" refer to the same memory location, which is false when username is obtained from user input (e.g., via Scanner or console), even if the characters are identical.

What should I do if I get this 1Z0-811 question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

Are there clue words in this question I should notice?

Yes — watch for: "most likely", "always". Probability qualifier — the question wants the most probable cause or outcome, not a guaranteed one. Eliminate low-probability options.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

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