Quick Answer
The answer is a=11 and b=20 because the expression `a++ > 10 && ++b > 20` relies on short-circuit evaluation with increment operators. In Java, the logical AND operator (`&&`) evaluates the left operand first; here, `a++` is a post-increment, so the comparison uses the original value of `a` (10), making `10 > 10` false. Since the left side is false, the entire `&&` condition is already determined, so the right operand `++b > 20` is never executed—this is the core of short-circuit evaluation. On the Oracle Java Foundations 1Z0-811 exam, this question tests your understanding of how operator precedence, post-increment behavior, and short-circuit logic interact. A common trap is assuming both sides run, but the short-circuit rule means `b` stays unchanged. Memory tip: think of `&&` as a gate that slams shut the moment it sees a false—only the left side’s increment happens.
This 1Z0-811 practice question tests your understanding of primitives, strings and operators. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Given: int a = 10; int b = 20; boolean flag = a++ > 10 && ++b > 20; What are the values of a and b after execution?
a=10, b=21
Why wrong: Incorrect: a is incremented to 11, and b is not incremented.
a=10, b=20
Why wrong: Incorrect: a is incremented to 11 due to post-increment.
a=11, b=21
Why wrong: Incorrect: due to short-circuit, b is not incremented.
a=11, b=20
Correct: a becomes 11, b remains 20 because the right side of && is not evaluated.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
a=11, b=20
The expression `a++ > 10 && ++b > 20` uses short-circuit evaluation. Since `a++` is post-increment, the comparison uses the original value of `a` (10) before incrementing, so `10 > 10` is false. Because the left operand is false, the `&&` operator short-circuits and the right operand `++b > 20` is never evaluated. Therefore, `a` is incremented to 11, but `b` remains 20, making option D correct.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
a=10, b=21
Why it's wrong here
Incorrect: a is incremented to 11, and b is not incremented.
a=10, b=20
Why it's wrong here
Incorrect: a is incremented to 11 due to post-increment.
a=11, b=21
Why it's wrong here
Incorrect: due to short-circuit, b is not incremented.
a=11, b=20
Why this is correct
Correct: a becomes 11, b remains 20 because the right side of && is not evaluated.
Related concept
Read the scenario before looking for a memorised answer.
Common exam traps
The trap here is that candidates often forget that post-increment `a++` uses the original value for the comparison but still increments `a` afterward, and they also overlook short-circuit evaluation, assuming both sides of `&&` are always evaluated.
Detailed technical explanation
Short-circuit evaluation is a key optimization in Java for logical operators `&&` and `||`. The `&&` operator evaluates the left operand first; if it is false, the right operand is never executed, which can prevent side effects like increments or method calls. In real-world code, this behavior is critical when the right operand has side effects (e.g., modifying a variable or throwing an exception) that should only occur if the left condition is true.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Primitives, Strings and Operators — This question tests Primitives, Strings and Operators — Read the scenario before looking for a memorised answer..
The correct answer is: a=11, b=20 — The expression `a++ > 10 && ++b > 20` uses short-circuit evaluation. Since `a++` is post-increment, the comparison uses the original value of `a` (10) before incrementing, so `10 > 10` is false. Because the left operand is false, the `&&` operator short-circuits and the right operand `++b > 20` is never evaluated. Therefore, `a` is incremented to 11, but `b` remains 20, making option D correct.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jun 25, 2026
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