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Primitives, Strings and OperatorseasyMultiple ChoiceObjective-mapped

1Z0-811 Primitives, Strings and Operators Practice Question

A junior developer wrote the following code to compare two strings entered by a user: if (username == "admin") { grantAccess(); } else { denyAccess(); }. The code always denies access even when the user enters 'admin'. What is the most likely cause, and how should the code be fixed?

⚠ Common exam trap

Oracle Java Foundations exam often tests the distinction between reference equality (==) and value equality (.equals()) for String objects, and the trap here is that candidates may think the issue is case sensitivity or whitespace, when the fundamental problem is the use of the wrong comparison operator.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

The strings are compared using == which checks reference equality. Use username.equals("admin") instead.

In Java, the == operator compares object references, not the actual content of strings. When comparing two String objects for logical equality, the .equals() method must be used. The code if (username == "admin") checks whether username and the string literal "admin" refer to the same memory location, which is false when username is obtained from user input (e.g., via Scanner or console), even if the characters are identical.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • The input string has leading or trailing spaces. Use username.trim().equals("admin") instead.

    Why it's wrong here

    Possible but less likely; not the most likely cause.

  • The variable username is null, causing a NullPointerException that is caught and denied access. Add a null check.

    Why it's wrong here

    NullPointerException would crash, not just deny.

  • The strings are compared using == which is case-sensitive. Use username.equalsIgnoreCase("admin") instead.

    Why it's wrong here

    Case-sensitivity is not the issue.

  • The strings are compared using == which checks reference equality. Use username.equals("admin") instead.

    Why this is correct

    equals compares content.

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