This 1Z0-811 practice question tests your understanding of primitives, strings and operators. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Refer to the exhibit.
public class OperatorTest {
public static void main(String[] args) {
int x = 3;
int y = ++x * x++;
System.out.println(x + "," + y);
}
}What is the output?
Refer to the exhibit.
public class OperatorTest {
public static void main(String[] args) {
int x = 3;
int y = ++x * x++;
System.out.println(x + "," + y);
}
}5,16
As explained.
4,16
Why wrong: x is incremented twice.
4,12
Why wrong: Incorrect.
5,12
Why wrong: Incorrect product.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
5,16
The code initializes `int x = 5;` and `int y = 16;` and then prints them using `System.out.print(x + "," + y);`. Since there are no operations that change the values, the output is simply the initial values: 5,16. Therefore, option A is correct.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
5,16
Why this is correct
As explained.
Related concept
Read the scenario before looking for a memorised answer.
4,16
Why it's wrong here
x is incremented twice.
4,12
Why it's wrong here
Incorrect.
5,12
Why it's wrong here
Incorrect product.
Common exam traps
This question tests simple variable initialization and output. The trap is that candidates might overthink and assume some operation changes the values, but since no operations are present, the output is simply the initial values. The comma in System.out.print is just a string literal, not a separator for multiple arguments.
Detailed technical explanation
Post-increment (`x++`) uses the current value in the expression, then increments the variable; pre-decrement (`--y`) decrements first, then uses the new value. This distinction is defined in the Java Language Specification (JLS §15.14.2 and §15.15.2). In real-world code, such as loop counters or index manipulation, misunderstanding these operators can lead to off-by-one errors or incorrect state updates.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Primitives, Strings and Operators — This question tests Primitives, Strings and Operators — Read the scenario before looking for a memorised answer..
The correct answer is: 5,16 — The code initializes `int x = 5;` and `int y = 16;` and then prints them using `System.out.print(x + "," + y);`. Since there are no operations that change the values, the output is simply the initial values: 5,16. Therefore, option A is correct.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jul 4, 2026
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