CCNA Practice Test 11 — 15 Questions

Question 1

R1 and R2 are connected via a GigabitEthernet link in the same IPv4 subnet, and both routers have OSPF configured in the same area. However, R1 is not learning any OSPF routes from R2. What is the most likely cause?

Accepted Answer

GigabitEthernet0/0 is configured as a passive OSPF interface on R1.. The most likely reason is that one side has the interface configured as passive, which prevents OSPF hello packets from being sent on that interface. In practical terms, the network statement alone does not guarantee neighbor formation. OSPF still needs active neighbor discovery on the link. If the interface is passive, the router advertises the connected network into OSPF but does not attempt to form an adjacency there.

This is a realistic routing troubleshooting pattern because the configuration can look mostly correct until you inspect the passive-interface setting.

Answer

The routers must use different OSPF process IDs to exchange routes.

Answer

The routers are in different IPv4 subnets.

Answer

OSPF can advertise routes only across serial links.

Question 2

A host is configured with 10.10.10.130/25. What is the network address of its subnet?

Accepted Answer

10.10.10.128. A /25 divides the address space into two blocks of 128 addresses. In plain language, the ranges are 0–127 and 128–255. Since the host ends in 130, it belongs to the 128–255 half. That means the network address is 10.10.10.128.

This is a common subnet-boundary question because it tests whether you can map a host address into the correct prefix block quickly and confidently.

Answer

10.10.10.0

Answer

10.10.10.64

Answer

10.10.10.255

Question 3

A host address is 192.168.1.14/29. Which address is the broadcast address for that host’s subnet?

Accepted Answer

192.168.1.15. A /29 uses blocks of 8 addresses. In plain language, the subnets in the last octet move in increments of 8: 0–7, 8–15, 16–23, and so on. Since the host address ends in 14, it belongs to the 8–15 block. In that block, the last address is the broadcast address, so the broadcast is 192.168.1.15.

This is a classic subnetting pattern because it requires you to place the host inside the correct block and then identify the last address in that block rather than guessing based on the host value itself.

Answer

192.168.1.7

Answer

192.168.1.14

Answer

192.168.1.16

Question 4

A network troubleshooter is using Cisco IOS-XE's embedded packet capture feature to capture traffic on an interface and then analyze it in Wireshark to isolate a Layer 2 or Layer 3 fault. Which of the following sequences represents the correct order of steps?

Accepted Answer

Define the capture point with interface and optional filter, start the capture, stop the capture, export the capture file, then analyze in Wireshark.. The correct workflow is to first define the capture point (interface and any filters), then start the capture, stop it when sufficient data is collected, export the captured packets to a file, and finally open that file in Wireshark for analysis. Starting the capture before defining the point, exporting before stopping, or defining the point after stopping all result in an invalid or incomplete capture process.

Answer

Start the capture, define the capture point with interface and filter, stop the capture, export the capture file, then analyze in Wireshark.

Answer

Define the capture point, start the capture, export the capture file, stop the capture, then analyze in Wireshark.

Answer

Start the capture, stop the capture, define the capture point, export the capture file, then analyze in Wireshark.

Question 5

Which TWO statements correctly describe the configuration and verification of IPv4 and IPv6 parameters for host connectivity?

Accepted Answer

On a Windows host, the default gateway IPv4 address must be on the same subnet as the host's IPv4 address.. Option A is correct because for a host to reach outside its subnet, the default gateway's IP must be in the same subnet; otherwise the host cannot ARP for the gateway's MAC and traffic will fail. Option D is correct because DNS server addresses can be set manually or assigned via DHCP. Option B is wrong because IPv6 gateways must be on the same local link, not any global unicast address on the internet. Option C is wrong because the subnet mask defines the network/subnet portion of an IPv4 address, not the host portion. Option E is wrong because DNS is used for name resolution; local IP communication on the same subnet works without DNS.

Answer

The IPv6 default gateway can be any global unicast address on the internet.

Answer

The subnet mask is used to define the host portion of an IPv4 address.

Answer

Configuring a DNS server is mandatory for a host to communicate with any other device on the same subnet.

Question 6

A host is assigned 192.168.10.33/28. Which subnet contains that host?

Accepted Answer

192.168.10.32/28. A /28 subnet uses blocks of 16 addresses. In plain language, the last octet ranges move in increments of 16: 0–15, 16–31, 32–47, 48–63, and so on. Since the host address ends in 33, it belongs to the 32–47 block. That means the containing subnet is 192.168.10.32/28.

This style of subnetting question is common because it tests whether you can identify the correct network boundary quickly. The key is to recognize the block size from the prefix and then place the address inside the correct interval without confusing the host with the network address.

Answer

192.168.10.16/28

Answer

192.168.10.48/28

Answer

192.168.10.0/28

Question 7

Users in VLAN 60 on switch SW2 cannot reach the default gateway located on switch SW1. The trunk between SW1 and SW2 is operational and allows VLAN 60. What is the most likely reason for this issue?

Accepted Answer

VLAN 60 does not exist locally on SW2.. VLAN 60 has not been created locally on SW2, even though the trunk can carry its traffic. A switch never processes VLAN traffic for a VLAN it doesn't know about; it discards tagged frames from the trunk destined for that VLAN and prevents access ports from assigning frames to it. (A) is correct. (B) is incorrect because native VLAN configuration only affects untagged frames—changing it to 60 is unnecessary for tagged VLAN 60 traffic. (C) is incorrect because the trunk is already configured to allow VLAN 60, so trunk filtering isn't the problem. (D) is incorrect because a default gateway is simply an IP address on a router or Layer 3 switch interface (like SVIs) and does not require a loopback on SW2.

Answer

The native VLAN must be changed to 60 on both switches.

Answer

VLAN 60 is not allowed on the trunk link.

Answer

The default gateway must be configured as a loopback on SW2.

Question 8

Which single OSI model layer is responsible for both end‑to‑end reliable data delivery and segmenting data into smaller units?

Accepted Answer

Transport layer (Layer 4). The Transport layer (Layer 4) is the only layer that ensures end‑to‑end reliable delivery using protocols like TCP that provide acknowledgements, sequencing, and retransmissions. At the same time, it segments large application data streams into smaller segments suitable for transmission. The Data Link layer (Layer 2) handles hop‑by‑hop framing but not end‑to‑end reliability. The Network layer (Layer 3) routes packets but does not guarantee delivery. The Session layer (Layer 5) manages sessions, not reliability or segmentation.

Answer

Data Link layer (Layer 2)

Answer

Network layer (Layer 3)

Answer

Session layer (Layer 5)

Question 9

A host uses address 192.168.5.126/25. Which address is the broadcast address for its subnet?

Accepted Answer

192.168.5.127. A /25 divides the /24 into two halves: 0–127 and 128–255. In plain language, the host address 192.168.5.126 is in the lower half, which runs from .0 through .127. The last address in that block is the broadcast address, so the broadcast is 192.168.5.127.

This is a classic subnetting question because it checks whether you can identify the correct block and then select the last address in that block as the broadcast address.

Answer

192.168.5.63

Answer

192.168.5.128

Answer

192.168.5.255

Question 10

A host is configured with IP address 10.10.40.78/28. Which subnet contains that host?

Accepted Answer

10.10.40.64/28. A /28 subnet has a block size of 16. In simple terms, the fourth-octet ranges are 0–15, 16–31, 32–47, 48–63, 64–79, 80–95, and so on. Because 78 falls inside the 64–79 block, the network address for this host’s subnet is 10.10.40.64/28.

This style of subnetting question checks whether you can move from prefix length to block size and then place the host into the correct range. The common mistake is choosing the nearest familiar-looking number instead of the actual block boundary.

Answer

10.10.40.48/28

Answer

10.10.40.72/28

Answer

10.10.40.80/28

Question 11

R1 has the following static route configured:

ip route 0.0.0.0 0.0.0.0 203.0.113.1

What does this route accomplish?

Accepted Answer

It creates a default route used when no more specific route exists.. This command creates a default static route. In everyday terms, it tells the router, “If you do not know a more specific way to reach a destination, send the traffic to 203.0.113.1.” That next-hop address usually points toward an upstream router or ISP edge. The command does not describe one specific remote network; it represents every destination not otherwise matched by a more specific entry.

At the routing-table level, `0.0.0.0 0.0.0.0` is the broadest possible IPv4 prefix. Because it matches everything, it is used only when nothing more specific exists.

Answer

It blocks unknown destinations from leaving the router.

Answer

It creates a host route to 203.0.113.1 only.

Answer

It advertises all connected routes into OSPF.

Question 12

Which TWO of the following are correct regarding Cisco SFP/SFP+ transceivers and their supported cable types?

Accepted Answer

A 1000BASE-T SFP transceiver can operate over Category 5e UTP cable up to 100 meters.. Correct answers are B and C. A 1000BASE-T SFP transceiver operates over Cat 5e or better UTP up to 100 meters as defined by IEEE 802.3ab, making B true. A 10GBASE-LR SFP+ transceiver supports up to 10 km over single-mode fiber, making C true. Option A is false because standard SFP+ fiber transceivers are not designed for UTP cabling; they require fiber or direct‑attach copper cables. (10GBASE‑T copper SFP+ modules exist but are rarely used in CCNA contexts and are not the typical SFP+ referenced.) Option D is false because 1000BASE‑SX has a maximum distance of 550 meters over multimode fiber, not 5 km. Option E is false because SFP+ transceivers have a larger form factor and do not fit into SFP slots; only SFP modules can fit into SFP+ slots (backward compatibility works the other way).

Answer

A standard SFP+ fiber transceiver can be used with Category 6a UTP cable to achieve 10 Gbps over 100 meters.

Answer

An SFP transceiver for 1000BASE-SX can achieve distances up to 5 kilometers over multimode fiber.

Answer

SFP+ transceivers are backward compatible with SFP slots and can operate at 1 Gbps if the module supports it.

Question 13

A host is configured with IP address 192.168.50.94/27. Which subnet contains that host?

Accepted Answer

192.168.50.64/27. A /27 subnet has a block size of 32. In simple terms, the fourth-octet ranges are 0–31, 32–63, 64–95, 96–127, and so on. Because 94 falls inside the 64–95 range, the network address for the host’s subnet is 192.168.50.64/27.

This kind of question tests whether you can move from prefix length to block size and then place the host inside the correct interval. The most common mistake is choosing a nearby boundary like 96 or 32 without calculating the actual block that contains the address.

Answer

192.168.50.32/27

Answer

192.168.50.96/27

Answer

192.168.50.0/27

Question 14

What prefix length corresponds to the subnet mask 255.255.255.248?

Accepted Answer

/29. The mask 255.255.255.248 corresponds to /29. In practical terms, the first three octets provide 24 network bits, and the value 248 in the last octet is 11111000 in binary, which contributes 5 more network bits. That gives a total prefix length of 29.

This is a standard dotted-decimal to prefix conversion question. It matters because subnetting often requires you to move comfortably between both forms.

Answer

/28

Answer

/30

Answer

/27

Question 15

R1 and R2 are connected via Ethernet and are configured with OSPF, but they fail to form an adjacency. Upon checking the interface configurations, you see that R1’s interface is in OSPF area 0 while R2’s interface is in area 1, and both interfaces use default timers and are in the same subnet. What is the most likely reason?

Accepted Answer

The OSPF areas do not match on the shared segment.. The most likely cause is an OSPF area mismatch on the shared segment. R1 and R2 are in the same IP subnet and use default hello/dead timers, so neither subnet mismatch nor timer mismatch is the problem. OSPF can run on Ethernet interfaces. However, OSPF requires neighbors on the same link to agree on the area ID; here they differ, preventing adjacency. Option B is incorrect because OSPF process IDs are locally significant and do not need to match.

Answer

The routers must use the same process ID.

Answer

The interfaces are in different IPv4 subnets.

Answer

OSPF cannot run on Ethernet interfaces.

CCNA Practice Test 11 — 15 Questions

Exhibit

CCNA Practice Test 11 — 15 Questions

Exhibit