Fix 'Network Unreachable' from Management Interface: Configure Default Gateway
This VCP-DCV practice question tests your understanding of configure and manage vsphere networking. Match the stated requirement to the specific cloud service, access model, or configuration option — many options are valid in isolation but not for this scenario. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Exhibit
esxcli network ip dns server list
DNSServers: 10.0.0.1, 10.0.0.2
esxcli network ip interface list
vmk0: IP: 192.168.10.10/24 MAC: 00:50:56:ab:cd:01 MTU: 1500
vmk1: IP: 192.168.20.10/24 MAC: 00:50:56:ab:cd:02 MTU: 1500
Default gateway: 192.168.20.1
esxcli network ip route ipv4 list
Network Netmask Gateway Interface
0.0.0.0 0.0.0.0 192.168.20.1 vmk1
192.168.10.0 255.255.255.0 0.0.0.0 vmk0
192.168.20.0 255.255.255.0 0.0.0.0 vmk1
vmkping -I vmk0 10.0.0.1
Ping using interface vmk0 (192.168.10.10/24):
Connect to host 10.0.0.1: Network is unreachable
Refer to the exhibit. An engineer tries to ping the DNS server 10.0.0.1 from the management interface vmk0 but gets 'Network is unreachable'. What is the most likely cause?
Clue words in this question
Noticing these words before you look at the options changes how you read each choice.
Clue: "most likely"
Why it matters: Probability qualifier — the question wants the most probable cause or outcome, not a guaranteed one. Eliminate low-probability options.
Exhibit
esxcli network ip dns server list
DNSServers: 10.0.0.1, 10.0.0.2
esxcli network ip interface list
vmk0: IP: 192.168.10.10/24 MAC: 00:50:56:ab:cd:01 MTU: 1500
vmk1: IP: 192.168.20.10/24 MAC: 00:50:56:ab:cd:02 MTU: 1500
Default gateway: 192.168.20.1
esxcli network ip route ipv4 list
Network Netmask Gateway Interface
0.0.0.0 0.0.0.0 192.168.20.1 vmk1
192.168.10.0 255.255.255.0 0.0.0.0 vmk0
192.168.20.0 255.255.255.0 0.0.0.0 vmk1
vmkping -I vmk0 10.0.0.1
Ping using interface vmk0 (192.168.10.10/24):
Connect to host 10.0.0.1: Network is unreachable
A
The DNS server 10.0.0.1 is down.
Why wrong: The error 'Network is unreachable' indicates a routing issue, not that the server is down.
B
The MTU of 1500 is too small for DNS traffic.
Why wrong: MTU 1500 is standard and sufficient for DNS.
C
The vmk0 interface does not have a default gateway configured; the default gateway is on vmk1.
vmk0's subnet is 192.168.10.0/24, and there is no route for 10.0.0.1 via vmk0. The default route goes through vmk1, but vmk0 cannot use that gateway because it's on a different subnet.
D
The DNS server IP address is misconfigured.
Why wrong: The IP is listed correctly; the issue is routing.
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The vmk0 interface does not have a default gateway configured; the default gateway is on vmk1.
The routing table shows the default gateway is on vmk1 (192.168.20.1), but vmk0 is on a different subnet (192.168.10.0/24). Traffic from vmk0 to 10.0.0.1 is not directly reachable and must go through a gateway. Since there is no route for 10.0.0.0/24 or default route via vmk0, the kernel reports network unreachable. The correct fix is to add a default gateway on vmk0 or a specific route.
Key principle: Count usable hosts — not total addresses — and remember that the network and broadcast addresses are not available to hosts in standard IPv4 subnets.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
The DNS server 10.0.0.1 is down.
Why it's wrong here
The error 'Network is unreachable' indicates a routing issue, not that the server is down.
The vmk0 interface does not have a default gateway configured; the default gateway is on vmk1.
Why this is correct
vmk0's subnet is 192.168.10.0/24, and there is no route for 10.0.0.1 via vmk0. The default route goes through vmk1, but vmk0 cannot use that gateway because it's on a different subnet.
Clue confirmation
The clue word "most likely" in the question point toward this answer.
Common exam trap: usable hosts are not the same as total addresses
Subnetting questions often tempt you into counting all addresses. In normal IPv4 subnets, the network and broadcast addresses are not usable host addresses.
Detailed technical explanation
How to think about this question
Subnetting questions test whether you can identify the network, broadcast address, usable range, mask and correct subnet. Slow down enough to calculate the block size correctly.
KKey Concepts to Remember
CIDR notation defines the prefix length.
Block size helps identify subnet boundaries.
Network and broadcast addresses are not usable hosts in normal IPv4 subnets.
The required host count determines the smallest suitable subnet.
TExam Day Tips
→Write the block size before choosing the subnet.
→Check whether the question asks for hosts, subnets or a specific address range.
→Do not confuse /24, /25, /26 and /27 host counts.
Key takeaway
Count usable hosts — not total addresses — and remember that the network and broadcast addresses are not available to hosts in standard IPv4 subnets.
Real-world example
How this comes up in practice
A network engineer segments a warehouse floor into three subnets: 20 scanners, 5 printers, and 2 management hosts. Picking the wrong mask wastes addresses or leaves too few usable hosts. Exam questions test whether you can apply CIDR notation, calculate block size, and identify the correct usable-host range for a given prefix.
Visual reference
What to study next
Got this wrong? Here's your next step.
Review block sizes, usable host formulas (2^n − 2), and how to find network and broadcast addresses for /24 through /30. Then practise related VCP-DCV subnetting questions on CIDR, address ranges, and subnet selection.
Configure and Manage vSphere Networking — This question tests Configure and Manage vSphere Networking — CIDR notation defines the prefix length..
What is the correct answer to this question?
The correct answer is: The vmk0 interface does not have a default gateway configured; the default gateway is on vmk1. — The routing table shows the default gateway is on vmk1 (192.168.20.1), but vmk0 is on a different subnet (192.168.10.0/24). Traffic from vmk0 to 10.0.0.1 is not directly reachable and must go through a gateway. Since there is no route for 10.0.0.0/24 or default route via vmk0, the kernel reports network unreachable. The correct fix is to add a default gateway on vmk0 or a specific route.
What should I do if I get this VCP-DCV question wrong?
Review block sizes, usable host formulas (2^n − 2), and how to find network and broadcast addresses for /24 through /30. Then practise related VCP-DCV subnetting questions on CIDR, address ranges, and subnet selection.
Are there clue words in this question I should notice?
Yes — watch for: "most likely". Probability qualifier — the question wants the most probable cause or outcome, not a guaranteed one. Eliminate low-probability options.
What is the key concept behind this question?
CIDR notation defines the prefix length.
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