VCP-DCV Configure and Manage vSphere Storage Practice Question
Exhibit
vmkfstools -P -v 10 /vmfs/volumes/datastore1 VMFS version 6.82 Number of extents: 2 Extent 0: /vmfs/devices/disks/naa.6000eb3a10e71d0023f04b28b6544000:1 offset: 0, size: 1048576 (blocks), block size: 1MB Extent 1: /vmfs/devices/disks/naa.6000eb3a10e71d0023f04b28b6544001:1 offset: 0, size: 2097152 (blocks), block size: 1MB
Refer to the exhibit. An administrator runs the 'vmkfstools -P -v 10' command on a datastore. What is the total capacity of the datastore?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
3 TB
The vmkfstools -P -v 10 command displays the datastore's extent information. The output shows two extents: one with 1,048,576 blocks and another with 2,097,152 blocks, both using a 1 MB block size. Total blocks = 1,048,576 + 2,097,152 = 3,145,728 blocks. Since each block is 1 MB, total capacity = 3,145,728 MB = 3,072 GB = 3 TB. Therefore, option C (3 TB) is correct. Option A (2.5 TB) and Option B (2 TB) are incorrect; Option D (1 TB) matches only the smaller extent.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
2.5 TB
Why it's wrong here
Not a sum of the extents.
- ✗
2 TB
Why it's wrong here
That is the size of the second extent only.
- ✓
3 TB
Why this is correct
1,048,576 + 2,097,152 = 3,145,728 blocks × 1 MB = 3,145,728 MB ≈ 3 TB.
- ✗
1 TB
Why it's wrong here
That is the size of the first extent only.
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Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
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