This 1Z0-829 practice question tests your understanding of utilizing java object-oriented approach. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
public class Outer {
private int x = 10;
class Inner {
private int x = 20;
void method() {
int x = 30;
System.out.println(x);
System.out.println(this.x);
System.out.println(Outer.this.x);
}
}
public static void main(String[] args) {
Outer.Inner inner = new Outer().new Inner();
inner.method();
}
}Refer to the exhibit. What is the output?
public class Outer {
private int x = 10;
class Inner {
private int x = 20;
void method() {
int x = 30;
System.out.println(x);
System.out.println(this.x);
System.out.println(Outer.this.x);
}
}
public static void main(String[] args) {
Outer.Inner inner = new Outer().new Inner();
inner.method();
}
}Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
30 20 10
The code uses a Deque (ArrayDeque) and calls push() to add elements, which adds them to the front of the deque (LIFO order). The for-each loop iterates from the head (first) to the tail (last), so it prints 30, 20, 10. Option B is correct because push() behaves like a stack, and iteration follows the deque's head-to-tail order.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Common exam traps
The trap here is that candidates confuse push() with add() (which adds to the tail) and assume the iteration order matches insertion order, rather than recognizing that push() places elements at the front for LIFO access.
Detailed technical explanation
ArrayDeque's push() method calls addFirst(), so elements are inserted at the head of the deque. The for-each loop uses the iterator, which traverses from head to tail (index 0 to size-1). This is a common pattern for implementing a stack with Deque, and the iteration order reflects the LIFO structure. In real-world scenarios, such as undo/redo operations or expression evaluation, understanding this order is critical for correct behavior.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Utilizing Java Object-Oriented Approach — This question tests Utilizing Java Object-Oriented Approach — Read the scenario before looking for a memorised answer..
The correct answer is: 30 20 10 — The code uses a Deque (ArrayDeque) and calls push() to add elements, which adds them to the front of the deque (LIFO order). The for-each loop iterates from the head (first) to the tail (last), so it prints 30, 20, 10. Option B is correct because push() behaves like a stack, and iteration follows the deque's head-to-tail order.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jul 4, 2026
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