Quick Answer
The answer is a compilation error because the variable `x` is declared inside the for loop block, and its scope is strictly limited to that block. In Java, any variable declared within a pair of curly braces—including the body of a `for` loop—has block scope, meaning it cannot be accessed outside those braces. The `System.out.println(x);` statement lies outside the loop, so the compiler cannot find the symbol `x`, resulting in a 'cannot find symbol' error. On the Oracle Java Foundations 1Z0-811 exam, this question tests your understanding of variable scope in for loops and block-level scoping rules, a common trap where candidates mistakenly think `x` persists after the loop ends. Remember the memory tip: "Braces bound the variable—outside the braces, the variable vanishes."
This 1Z0-811 practice question tests your understanding of java basics and syntax. The scenario asks you to isolate a root cause — eliminate options that address a different problem before choosing. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Consider: for(int i=0;i<10;i++) { int x = i; } System.out.println(x); What is the result?
9
Why wrong: Incorrect. x is not accessible outside the loop.
10
Why wrong: Incorrect. x is not accessible outside the loop.
Compilation error
Correct. x is out of scope.
0
Why wrong: Incorrect. x is not accessible outside the loop.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
Compilation error
The variable `x` is declared inside the `for` loop block, so its scope is limited to that block. Attempting to use `x` outside the loop (in the `System.out.println(x);` statement) causes a compilation error because `x` is not in scope at that point. The Java compiler enforces block-level scoping rules, and any reference to a variable outside its declared block results in a 'cannot find symbol' error.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
9
Why it's wrong here
Incorrect. x is not accessible outside the loop.
10
Why it's wrong here
Incorrect. x is not accessible outside the loop.
Compilation error
Why this is correct
Correct. x is out of scope.
Related concept
Read the scenario before looking for a memorised answer.
0
Why it's wrong here
Incorrect. x is not accessible outside the loop.
Common exam traps
The trap here is that candidates often overlook Java's strict block scoping rules and assume a variable declared inside a loop is accessible after the loop, confusing it with languages that have function-level scoping or with the loop variable `i` itself, which is also scoped to the loop block.
Detailed technical explanation
In Java, block-scoped variables (declared inside a `for`, `if`, or any block `{}`) are only accessible within that block. The Java Language Specification (JLS §6.3) defines the scope of a local variable declaration as the rest of the block in which it is declared. This prevents accidental use of variables outside their intended context, reducing bugs. A real-world scenario is when a developer mistakenly tries to use a loop counter after the loop, leading to a compile-time error that forces better code structure.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Java Basics and Syntax — study guide chapter
Learn the concepts, then practise the questions
Java Basics and Syntax practice questions
Targeted practice on this topic area only
All 1Z0-811 questions
509 questions across all exam domains
Oracle Java Foundations 1Z0-811 study guide
Full concept coverage aligned to exam objectives
1Z0-811 practice test guide
How to use practice tests most effectively before exam day
Related practice questions
Use these pages to review the topic behind this question. This is how one missed question becomes focused revision.
Practise 1Z0-811 questions linked to What is Java.
Practise 1Z0-811 questions linked to Java Basics and Syntax.
Practise 1Z0-811 questions linked to Primitives, Strings and Operators.
Practise 1Z0-811 questions linked to Control Flow and Loops.
Practise 1Z0-811 questions linked to Arrays and Methods.
Practise 1Z0-811 questions linked to Object-Oriented Programming.
Practise 1Z0-811 questions linked to Exception Handling and Development Tools.
Practise 1Z0-811 questions linked to 1Z0-811 fundamentals.
Practise 1Z0-811 questions linked to 1Z0-811 scenario.
Practise 1Z0-811 questions linked to 1Z0-811 troubleshooting.
Practice this exam
Short sessions build daily habit. Longer sessions build exam-day stamina. Try a timed session to simulate real conditions.
FAQ
Java Basics and Syntax — This question tests Java Basics and Syntax — Read the scenario before looking for a memorised answer..
The correct answer is: Compilation error — The variable `x` is declared inside the `for` loop block, so its scope is limited to that block. Attempting to use `x` outside the loop (in the `System.out.println(x);` statement) causes a compilation error because `x` is not in scope at that point. The Java compiler enforces block-level scoping rules, and any reference to a variable outside its declared block results in a 'cannot find symbol' error.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
About these practice questions
Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
Last reviewed: Jun 25, 2026
This 1Z0-811 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-811 exam.
Question Discussion
Share a tip, memory trick, or ask about the reasoning behind this question. Do not post real exam questions, leaked content, braindumps, or copyrighted exam material. Comments are moderated and may be removed without notice.
Sign in to join the discussion.