This 1Z0-811 practice question tests your understanding of object-oriented programming. The scenario asks you to isolate a root cause — eliminate options that address a different problem before choosing. A key principle to apply: default method conflict. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Exhibit
Refer to the exhibit.
interface Printable {
default void print() { System.out.println("Printable"); }
}
interface Showable {
default void print() { System.out.println("Showable"); }
}
class Document implements Printable, Showable {
// no override
}
What is the result of: new Document().print();
Exhibit
Refer to the exhibit.
interface Printable {
default void print() { System.out.println("Printable"); }
}
interface Showable {
default void print() { System.out.println("Showable"); }
}
class Document implements Printable, Showable {
// no override
}
A
Printable
Why wrong: Incorrect. The code never runs to produce a result; it fails at compile time.
B
Runtime exception
Why wrong: Incorrect. A runtime exception is not thrown because the program never compiles.
C
Compilation fails
Correct. The ambiguity between the two default `print()` methods causes a compilation failure.
D
Showable
Why wrong: Incorrect. The code does not compile, so `Showable` is not printed.
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Compilation fails
The code fails to compile because the class `Document` likely implements two interfaces, such as `Printable` and `Showable`, each declaring a default `print()` method. This creates a diamond problem where the compiler cannot determine which default method to use, resulting in a compilation error unless `Document` overrides `print()`. The error occurs at compile time, not runtime.
Key principle: Default method conflict
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
Printable
Why it's wrong here
Incorrect. The code never runs to produce a result; it fails at compile time.
✗
Runtime exception
Why it's wrong here
Incorrect. A runtime exception is not thrown because the program never compiles.
✓
Compilation fails
Why this is correct
Correct. The ambiguity between the two default `print()` methods causes a compilation failure.
Related concept
Default method conflict
✗
Showable
Why it's wrong here
Incorrect. The code does not compile, so `Showable` is not printed.
Common exam traps
Common exam trap: answer the scenario, not the keyword
Oracle often tests the distinction between compilation errors and runtime exceptions. In this case, candidates may incorrectly think the missing method leads to a runtime exception, but the ambiguity between two default methods causes a compile-time failure.
Trap categories for this question
Command / output trap
Incorrect. The code does not compile, so `Showable` is not printed.
Detailed technical explanation
How to think about this question
In Java, method resolution is performed at compile time based on the declared type of the reference. If the method is not found in the class hierarchy, the compiler reports a 'cannot find symbol' error. This ensures type safety and prevents runtime errors from missing methods. Real-world scenarios include forgetting to import a library or mistyping a method name.
KKey Concepts to Remember
Default method conflict
Compile-time error vs runtime exception
TExam Day Tips
→Watch for words such as best, first, most likely and least administrative effort.
→Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Default method conflict
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-811 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Default method conflict Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Review default method conflict, then practise related 1Z0-811 questions on the same topic to reinforce the concept.
The correct answer is: Compilation fails — The code fails to compile because the class `Document` likely implements two interfaces, such as `Printable` and `Showable`, each declaring a default `print()` method. This creates a diamond problem where the compiler cannot determine which default method to use, resulting in a compilation error unless `Document` overrides `print()`. The error occurs at compile time, not runtime.
What should I do if I get this 1Z0-811 question wrong?
Review default method conflict, then practise related 1Z0-811 questions on the same topic to reinforce the concept.
What is the key concept behind this question?
Default method conflict
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Question Discussion
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