The answer is that the route 10.1.1.0/24 has one successor with a feasible distance of 131072 and is learned via 10.1.1.1. This is correct because the EIGRP topology verification VRF output explicitly shows the route in a Passive state with a single Routing Descriptor Block, indicating a stable, loop-free path where the Feasible Distance (FD) of 131072 represents the total metric to the destination, and the next hop 10.1.1.1 is the sole successor. On the Cisco CCNP ENARSI 300-410 exam, this command tests your ability to interpret EIGRP topology entries within a VRF-Lite context, often appearing in troubleshooting scenarios where you must distinguish between Passive and Active states or identify the number of successors. A common trap is confusing the reported distance (128256) with the feasible distance; remember that the FD is always the first metric in the parentheses. Memory tip: "Passive means no query, one successor means one path—check the FD, not the RD, for the true cost."
300-410 VRF-Lite Practice Question
This 300-410 practice question tests your understanding of vrf-lite. The scenario asks you to isolate a root cause — eliminate options that address a different problem before choosing. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A network engineer runs the following command to troubleshoot a VRF-Lite issue:
R1# show ip eigrp vrf CUSTOMER_B topology 10.1.1.0/24
Output:
IP-EIGRP (AS 100): Topology entry for 10.1.1.0/24 for VRF CUSTOMER_B
State is Passive, Query origin flag is 1, 1 Successor(s), FD is 131072
Routing Descriptor Blocks:
10.1.1.1 (GigabitEthernet0/1), from 10.1.1.1, Send flag is 0x0
Composite metric is (131072/128256), Route is Internal
Vector metric:
Minimum bandwidth is 100000 Kbit
Total delay is 100 microseconds
Reliability is 255/255
Load is 1/255
Minimum MTU is 1500
Hop count is 1
What does this output indicate?
Clue words in this question
Noticing these words before you look at the options changes how you read each choice.
Clue: "minimum / minimize"
Why it matters: Asks for the least resource use — fewest addresses, smallest subnet, lowest overhead. Eliminate over-provisioned options even if they would technically work.
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The route 10.1.1.0/24 has one successor with a feasible distance of 131072 and is learned via 10.1.1.1.
The 'show ip eigrp vrf topology' command displays the EIGRP topology table entry for a specific prefix within a VRF. The output shows the route 10.1.1.0/24 is in Passive state, meaning no EIGRP query is pending. It has one successor (the best path) with a feasible distance (FD) of 131072. The next hop is 10.1.1.1 via GigabitEthernet0/1.
Key principle: NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
The route 10.1.1.0/24 is in Active state, indicating an EIGRP query is in progress.
Why it's wrong here
Incorrect. The state is Passive, not Active.
✓
The route 10.1.1.0/24 has one successor with a feasible distance of 131072 and is learned via 10.1.1.1.
Why this is correct
Correct. The output shows one successor, FD 131072, and next hop 10.1.1.1.
Clue confirmation
The clue word "minimum / minimize" in the question point toward this answer.
Related concept
Static NAT maps one inside address to one outside address.
✗
The route 10.1.1.0/24 is an external EIGRP route redistributed into the VRF.
Why it's wrong here
Incorrect. The output says 'Route is Internal', not external.
✗
The route 10.1.1.0/24 has multiple successors due to equal-cost paths.
Why it's wrong here
Incorrect. There is only one successor listed in the Routing Descriptor Blocks.
Common exam traps
Common exam trap: NAT rules depend on direction and matching traffic
NAT is not only about the public address. The inside/outside interface roles and the ACL or rule that matches traffic are just as important.
Trap categories for this question
Command / output trap
Incorrect. The output says 'Route is Internal', not external.
Detailed technical explanation
How to think about this question
NAT questions usually test address translation, overload/PAT behaviour, static mappings and whether the right traffic is being translated. Read the interface direction and address terms carefully.
KKey Concepts to Remember
Static NAT maps one inside address to one outside address.
PAT allows many inside hosts to share one public address using ports.
Inside local and inside global describe the private and translated addresses.
NAT ACLs identify traffic for translation, not always security filtering.
TExam Day Tips
→Identify inside and outside interfaces first.
→Check whether the scenario needs static NAT, dynamic NAT or PAT.
→Do not confuse NAT matching ACLs with normal packet-filtering intent.
Key takeaway
NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.
Real-world example
How this comes up in practice
A small business has 20 workstations on the 192.168.1.0/24 network and one public IP from its ISP. The router uses PAT (NAT overload) so all 20 devices share one public address using different source ports. NAT questions test whether you understand the four address terms and which direction each translation applies.
Related glossary terms
Concepts from this question explained
These glossary pages explain the core terms tested in this 300-410 question in full detail.
Review the four NAT address types (inside local, inside global, outside local, outside global), PAT port overload, and static vs dynamic NAT use cases. Then practise related 300-410 NAT questions on configuration and troubleshooting.
VRF-Lite — This question tests VRF-Lite — Static NAT maps one inside address to one outside address..
What is the correct answer to this question?
The correct answer is: The route 10.1.1.0/24 has one successor with a feasible distance of 131072 and is learned via 10.1.1.1. — The 'show ip eigrp vrf topology' command displays the EIGRP topology table entry for a specific prefix within a VRF. The output shows the route 10.1.1.0/24 is in Passive state, meaning no EIGRP query is pending. It has one successor (the best path) with a feasible distance (FD) of 131072. The next hop is 10.1.1.1 via GigabitEthernet0/1.
What should I do if I get this 300-410 question wrong?
Review the four NAT address types (inside local, inside global, outside local, outside global), PAT port overload, and static vs dynamic NAT use cases. Then practise related 300-410 NAT questions on configuration and troubleshooting.
Are there clue words in this question I should notice?
Yes — watch for: "minimum / minimize". Asks for the least resource use — fewest addresses, smallest subnet, lowest overhead. Eliminate over-provisioned options even if they would technically work.
What is the key concept behind this question?
Static NAT maps one inside address to one outside address.
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