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ANS-C01 Network Implementation Practice Question

A company has an AWS Site-to-Site VPN connection between their on-premises network and a VPC. The VPN tunnel status shows 'UP'. However, instances in the VPC cannot ping an on-premises server at 192.168.1.10. Which step should be taken to troubleshoot?

⚠ Common exam trap

The trap here is that candidates see 'VPN tunnel status UP' and assume connectivity is fully functional, overlooking the critical requirement of a VPC route pointing to the virtual private gateway for traffic to traverse the tunnel.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

Verify that the VPC route table has a route to the on-premises network via the virtual private gateway

Even though the VPN tunnel is 'UP', traffic from the VPC to the on-premises network must be routed through the virtual private gateway (VGW). If the VPC route table does not contain a route for the on-premises CIDR (e.g., 192.168.1.0/24) pointing to the VGW, the instances have no path to reach the on-premises server, regardless of tunnel status.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • Verify that the internet gateway is attached to the VPC

    Why it's wrong here

    Internet gateway is not used for VPN traffic.

  • Verify that the VPC route table has a route to the on-premises network via the virtual private gateway

    Why this is correct

    Without this route, traffic from VPC to on-premises is dropped.

  • Verify that the security group for the instances allows outbound ICMP

    Why it's wrong here

    Security groups are stateful and allow outbound traffic by default.

  • Verify that the VPN tunnel is up on both ends

    Why it's wrong here

    The tunnel is already UP.

Visual reference

192.168.1.0 /24 256 addresses (254 usable) 192.168.1.0 /25 Subnet A 128 addr (126 usable) 192.168.1.128 /25 Subnet B 128 addr (126 usable) Borrowing 1 bit from host portion creates 2 subnets (/25)

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

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