VCP-DCV Configure and Manage vSphere Networking Practice Question
Exhibit
Refer to the exhibit.
<config>
<vswitch name="vSwitch0">
<portgroup name="VM Network">
<vlan>0</vlan>
<nicteaming>
<policy>
<failover>yes</failover>
<loadbalance>srcmac</loadbalance>
<active>vmnic0,vmnic1</active>
</policy>
</nicteaming>
</portgroup>
</vswitch>
</config>An administrator is reviewing the network configuration of a standard switch. The exhibit shows the current settings for a port group. Which change would improve load distribution for VM traffic?
⚠ Common exam trap
Candidates often confuse 'failover' with 'load balancing' and assume enabling failover (Option B) will distribute traffic, but failover only provides redundancy, not active load sharing, while Route based on IP hash (Option C) is the correct method for distributing VM traffic across multiple uplinks.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Change the load balancing policy to Route based on IP hash.
Route based on IP hash uses a hash of source and destination IP addresses to determine which uplink to use for each traffic flow, ensuring that all packets in a given flow use the same uplink while distributing different flows across multiple uplinks. This improves load distribution for VM traffic compared to the default Route based on the originating virtual port, which only considers the vNIC port ID and can lead to uneven distribution when multiple VMs share the same port group.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Change the VLAN ID to 100.
Why it's wrong here
VLAN does not affect load balancing.
- ✗
Enable failover on the port group.
Why it's wrong here
Failover is already enabled.
- ✓
Change the load balancing policy to Route based on IP hash.
Why this is correct
IP hash provides better distribution.
- ✗
Set one NIC as active and the other as standby.
Why it's wrong here
This would reduce throughput.
Go deeper
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Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
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