Quick Answer
The answer is 'Python', because when you reassign a variable in Python, the original string object remains unchanged due to string immutability. In the code, `t = s` makes both variables reference the same string object `'Python'`. When `s = s + '3.0'` executes, Python creates a brand new string object `'Python3.0'` and binds it to `s`, while `t` continues to point to the original immutable `'Python'` object. This tests your understanding of how variable assignment works with immutable types, a core concept for the Certified Associate Python Programmer PCAP exam. A common trap is assuming that reassigning `s` also changes `t`, but immutability means strings cannot be modified in place—only new objects are created. Remember the memory tip: "Immutable means I'm mutable? No—I'm fixed; reassignment just changes the label, not the object."
This PCAP practice question tests your understanding of strings. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Given the code: s = 'Python'; t = s; s = s + '3.0'. What is the value of t after these lines execute?
It raises an error because s was reassigned.
Why wrong: No error; reassignment is fine.
''
Why wrong: t is not affected by the reassignment of s.
'Python3.0'
Why wrong: If strings were mutable, t might change, but they are immutable.
'Python'
t originally pointed to the same object as s, but when s is reassigned, t still references the original 'Python'.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
'Python'
Option D is correct because strings in Python are immutable. The assignment `t = s` makes `t` reference the same string object as `s`. When `s = s + '3.0'` executes, a new string object `'Python3.0'` is created and bound to `s`, while `t` still references the original string `'Python'`. Thus, `t` remains `'Python'`.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
It raises an error because s was reassigned.
Why it's wrong here
No error; reassignment is fine.
''
Why it's wrong here
t is not affected by the reassignment of s.
'Python3.0'
Why it's wrong here
If strings were mutable, t might change, but they are immutable.
'Python'
Why this is correct
t originally pointed to the same object as s, but when s is reassigned, t still references the original 'Python'.
Related concept
Read the scenario before looking for a memorised answer.
Common exam traps
Python Institute often tests the misconception that variable assignment creates a copy of the value, when in fact it creates a reference; candidates mistakenly think `t` will reflect the new value of `s` after reassignment.
Detailed technical explanation
Under the hood, Python strings are immutable sequences of Unicode code points. The concatenation `s + '3.0'` does not modify the original string; it allocates a new string object in memory. This immutability is crucial for performance optimizations like string interning and safe sharing of references across variables. In real-world scenarios, this behavior prevents unintended side effects when passing strings to functions or using them as dictionary keys.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A media company stores terabytes of video archives that are accessed once a year for audit purposes. Moving these objects to a cold storage tier (Azure Archive, S3 Glacier, or Google Nearline) costs a fraction of hot storage. Questions like this test whether you understand storage tiers, access frequency tradeoffs, and retrieval latency requirements.
What to study next
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FAQ
Strings — This question tests Strings — Read the scenario before looking for a memorised answer..
The correct answer is: 'Python' — Option D is correct because strings in Python are immutable. The assignment `t = s` makes `t` reference the same string object as `s`. When `s = s + '3.0'` executes, a new string object `'Python3.0'` is created and bound to `s`, while `t` still references the original string `'Python'`. Thus, `t` remains `'Python'`.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jun 30, 2026
This PCAP practice question is part of Courseiva's free Python Institute certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the PCAP exam.
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