1Z0-829 Controlling Program Flow Practice Question
Which TWO of the following are valid forms of the switch statement/expression in Java?
⚠ Common exam trap
A common mix-up: candidates confuse the syntax of switch statements and switch expressions, mistakenly applying arrow syntax or yield to a switch statement, or thinking break can carry a value like in some other languages.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
switch(x) { case 1: System.out.println("one"); break; }
It uses the traditional switch statement syntax with a colon after the case label, a statement to execute, and a break statement to prevent fall-through. This is a valid and long-standing form of the switch statement in Java.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
switch(x) { case 1 -> "one"; }
Why it's wrong here
Missing semicolon or yield; arrow form requires expression or block.
- ✓
switch(x) { case 1: System.out.println("one"); break; }
Why this is correct
Valid traditional switch statement.
- ✓
String r = switch(x) { case 1 -> "one"; default -> "other"; };
Why this is correct
Valid switch expression with arrow.
- ✗
String r = switch(x) { case 1: break "one"; };
Why it's wrong here
break cannot return a value; use yield in arrow form.
- ✗
switch(x) { case 1: yield "one"; }
Why it's wrong here
Colon form does not support yield; yield is for arrow form only.
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