- A
switch(x) { case 1 -> "one"; }
Why wrong: Missing semicolon or yield; arrow form requires expression or block.
- B
switch(x) { case 1: System.out.println("one"); break; }
Valid traditional switch statement.
- C
String r = switch(x) { case 1 -> "one"; default -> "other"; };
Valid switch expression with arrow.
- D
String r = switch(x) { case 1: break "one"; };
Why wrong: break cannot return a value; use yield in arrow form.
- E
switch(x) { case 1: yield "one"; }
Why wrong: Colon form does not support yield; yield is for arrow form only.
Quick Answer
The answer is the traditional switch statement with colons and break statements, as well as the arrow-form switch expression that assigns a value to a variable. Option B is correct because it uses the classic colon syntax with explicit break statements to prevent fall-through, which has been a valid switch form since Java’s earliest versions. Option A is correct because it demonstrates the modern arrow syntax introduced in Java 14, where the switch expression directly yields a value without fall-through, making it both a statement and an expression. On the Oracle Certified Professional Java SE 17 Developer 1Z0-829 exam, this question tests your ability to distinguish between valid switch forms—especially the subtle difference between a switch statement (which can use colons or arrows) and a switch expression (which must use arrows and assign a result). A common trap is confusing the older colon form with the newer arrow form, or forgetting that a switch expression requires a default branch when not exhaustive. Memory tip: colons need breaks, arrows give values.
1Z0-829 Controlling Program Flow Practice Question
This 1Z0-829 practice question tests your understanding of controlling program flow. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Which TWO of the following are valid forms of the switch statement/expression in Java?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
switch(x) { case 1: System.out.println("one"); break; }
Option B is correct because it uses the traditional switch statement syntax with a colon after the case label, a statement to execute, and a break statement to prevent fall-through. This is a valid and long-standing form of the switch statement in Java.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
switch(x) { case 1 -> "one"; }
Why it's wrong here
Missing semicolon or yield; arrow form requires expression or block.
- ✓
switch(x) { case 1: System.out.println("one"); break; }
Why this is correct
Valid traditional switch statement.
Related concept
Read the scenario before looking for a memorised answer.
- ✓
String r = switch(x) { case 1 -> "one"; default -> "other"; };
Why this is correct
Valid switch expression with arrow.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
String r = switch(x) { case 1: break "one"; };
Why it's wrong here
break cannot return a value; use yield in arrow form.
- ✗
switch(x) { case 1: yield "one"; }
Why it's wrong here
Colon form does not support yield; yield is for arrow form only.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates often confuse the syntax of switch statements and switch expressions, mistakenly applying arrow syntax or yield to a switch statement, or thinking break can carry a value like in some other languages.
Detailed technical explanation
How to think about this question
In Java, switch statements and switch expressions are distinct: a switch statement uses colon-case with break to control flow, while a switch expression uses arrow-case or colon-case with yield to produce a value. The arrow syntax (->) in a switch expression is a shorthand that eliminates fall-through and implicitly yields the value on the right side. The yield keyword was introduced in Java 14 for switch expressions to explicitly return a value from a colon-case block, but it cannot be used in a traditional switch statement.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
- →
Controlling Program Flow — study guide chapter
Learn the concepts, then practise the questions
- →
Controlling Program Flow practice questions
Targeted practice on this topic area only
- →
All 1Z0-829 questions
509 questions across all exam domains
- →
Oracle Certified Professional Java SE 17 Developer 1Z0-829 study guide
Full concept coverage aligned to exam objectives
- →
1Z0-829 practice test guide
How to use practice tests most effectively before exam day
Related practice questions
Related 1Z0-829 practice-question pages
Use these pages to review the topic behind this question. This is how one missed question becomes focused revision.
Handling Date, Time, Text, Numeric and Boolean Values practice questions
Practise 1Z0-829 questions linked to Handling Date, Time, Text, Numeric and Boolean Values.
Controlling Program Flow practice questions
Practise 1Z0-829 questions linked to Controlling Program Flow.
Utilizing Java Object-Oriented Approach practice questions
Practise 1Z0-829 questions linked to Utilizing Java Object-Oriented Approach.
Handling Exceptions practice questions
Practise 1Z0-829 questions linked to Handling Exceptions.
Working with Arrays and Collections practice questions
Practise 1Z0-829 questions linked to Working with Arrays and Collections.
Working with Streams and Lambda Expressions practice questions
Practise 1Z0-829 questions linked to Working with Streams and Lambda Expressions.
Java Platform Overview and Packaging practice questions
Practise 1Z0-829 questions linked to Java Platform Overview and Packaging.
Java I/O API and Securing Applications practice questions
Practise 1Z0-829 questions linked to Java I/O API and Securing Applications.
1Z0-829 fundamentals practice questions
Practise 1Z0-829 questions linked to 1Z0-829 fundamentals.
1Z0-829 scenario practice questions
Practise 1Z0-829 questions linked to 1Z0-829 scenario.
1Z0-829 troubleshooting practice questions
Practise 1Z0-829 questions linked to 1Z0-829 troubleshooting.
Practice this exam
Start a free 1Z0-829 practice session
Short sessions build daily habit. Longer sessions build exam-day stamina. Try a timed session to simulate real conditions.
FAQ
Questions learners often ask
What does this 1Z0-829 question test?
Controlling Program Flow — This question tests Controlling Program Flow — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: switch(x) { case 1: System.out.println("one"); break; } — Option B is correct because it uses the traditional switch statement syntax with a colon after the case label, a statement to execute, and a break statement to prevent fall-through. This is a valid and long-standing form of the switch statement in Java.
What should I do if I get this 1Z0-829 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
About these practice questions
Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
Last reviewed: Jun 25, 2026
This 1Z0-829 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-829 exam.
Question Discussion
Share a tip, memory trick, or ask about the reasoning behind this question. Do not post real exam questions, leaked content, braindumps, or copyrighted exam material. Comments are moderated and may be removed without notice.
Sign in to join the discussion.