This 1Z0-829 practice question tests your understanding of controlling program flow. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Refer to the exhibit.
```
int count = 0;
for (int i = 0; i < 5; i++) {
if (i == 3) {
break;
}
count++;
}
System.out.println(count);
```What is the output?
Refer to the exhibit.
```
int count = 0;
for (int i = 0; i < 5; i++) {
if (i == 3) {
break;
}
count++;
}
System.out.println(count);
```3
Loop runs for i=0,1,2 then breaks.
0
Why wrong: count is incremented.
4
Why wrong: Break at i=3 prevents increment.
5
Why wrong: Loop exits early.
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
3
The correct answer is 3 because the code uses a `for` loop that increments `i` from 0 to 4, but the loop body only executes when `i < 3` due to the condition `i < 3`. The loop runs for `i = 0, 1, 2` (three iterations), and each time `count` is incremented by 1, resulting in `count = 3`. The final value of `count` is printed.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
3
Why this is correct
Loop runs for i=0,1,2 then breaks.
Related concept
Read the scenario before looking for a memorised answer.
0
Why it's wrong here
count is incremented.
4
Why it's wrong here
Break at i=3 prevents increment.
5
Why it's wrong here
Loop exits early.
Common exam traps
The trap here is that candidates often miscount the number of iterations by including the value where the condition becomes false, leading to an off-by-one error, or they confuse the loop's upper bound (3) with the number of iterations.
Detailed technical explanation
In Java, the `for` loop evaluates the condition before each iteration; when `i` reaches 3, the condition `i < 3` is false, and the loop terminates. The loop variable `i` is incremented after each iteration, so the loop runs exactly for `i = 0, 1, 2`. This is a classic off-by-one scenario where the condition uses `<` instead of `<=`, which is a common source of errors in boundary conditions.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Controlling Program Flow — This question tests Controlling Program Flow — Read the scenario before looking for a memorised answer..
The correct answer is: 3 — The correct answer is 3 because the code uses a `for` loop that increments `i` from 0 to 4, but the loop body only executes when `i < 3` due to the condition `i < 3`. The loop runs for `i = 0, 1, 2` (three iterations), and each time `count` is incremented by 1, resulting in `count = 3`. The final value of `count` is printed.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jun 11, 2026
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