1Z0-829 Controlling Program Flow Practice Question
What is the output of the following code snippet? int x = 5; if(x > 0) { System.out.print('A'); } else if(x > 2) { System.out.print('B'); } else { System.out.print('C'); }
⚠ Common exam trap
The trap here is that candidates mistakenly think the `else if` condition is also evaluated or that multiple branches can execute, confusing the if-else-if chain with a series of independent if statements.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
A
The condition `x > 0` evaluates to true (x = 5), so the code prints 'A' and then exits the entire if-else-if chain. The subsequent `else if` and `else` blocks are skipped entirely, so only 'A' is output.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
AB
Why it's wrong here
Only one branch executes.
- ✗
C
Why it's wrong here
The else branch is not reached because a prior condition was true.
- ✗
B
Why it's wrong here
The else-if branch is not reached because the first condition was true.
- ✓
A
Why this is correct
x > 0 is true, so the first branch executes and prints 'A'.
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Variation 1. Given the code snippet: int x = 10; if (x > 5) { System.out.print("A"); } else if (x > 7) { System.out.print("B"); } else { System.out.print("C"); } What is the output?
easy- A.C
- B.ABC
- ✓ C.A
- D.B
Why C: The if-else chain evaluates conditions sequentially. Since x=10 satisfies x > 5, the first block executes and prints 'A'. The else if and else branches are skipped entirely because the first condition was true. Thus, only 'A' is output.
JA
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