Working with Arrays and Collections →mediumMultiple ChoiceObjective-mapped

1Z0-829 Working with Arrays and Collections Practice Question

Exhibit

Refer to the exhibit.
List<String> list = new ArrayList<>(List.of("a","b","c"));
list.removeIf(s -> s.equals("b"));
System.out.println(list);

What is the output of the above code?

⚠ Common exam trap

It's easy for candidates to confuse `remove(Object)` with `remove(int index)` and think the code removes the element at index 1 (which would be "b" as well), but the correct understanding is that `remove(Object)` removes by value, not by index.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

[a, c]

The code uses `List.remove(Object)` which removes the first occurrence of the specified element. After removing "b" from the list [a, b, c], the list becomes [a, c]. Option B is correct because the output is [a, c].

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
[a, b]
Why it's wrong here
Incorrect: only "c" would remain if "a" were removed.
✓
[a, c]
Why this is correct
Correct: "b" is removed, leaving a and c.
✗
[a, b, c]
Why it's wrong here
Incorrect: "b" is removed.
✗
[b, c]
Why it's wrong here
Incorrect: "a" should remain.
✗
Compilation fails
Why it's wrong here
The code compiles and runs successfully.

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1Z0-829 Working with Arrays and Collections Practice Question

Exhibit

Why each option matters

Option-by-option breakdown

Related to this question