1Z0-829 Controlling Program Flow Practice Question
This 1Z0-829 practice question tests your understanding of controlling program flow. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Exhibit
Refer to the exhibit.
public class Test {
public static void main(String[] args) {
int i = 0;
while (i < 5) {
if (i == 3) break;
i++;
}
System.out.println(i);
}
}
Refer to the exhibit.
public class Test {
public static void main(String[] args) {
int i = 0;
while (i < 5) {
if (i == 3) break;
i++;
}
System.out.println(i);
}
}
A
4
Why wrong: Incorrect; i is not incremented after break.
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
3
The code uses a `for` loop with `int i = 0; i < 5; ++i`. The loop increments `i` before each iteration check, but the initial value is 0. The loop runs while `i < 5`, so it iterates for `i = 0, 1, 2, 3, 4` — five iterations. However, the loop body contains `if (i == 3) break;`, which terminates the loop when `i` equals 3. At that point, the loop has executed for `i = 0, 1, 2` (three iterations), so `count` is incremented three times, resulting in output 3.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
4
Why it's wrong here
Incorrect; i is not incremented after break.
✓
3
Why this is correct
Correct: break at i=3 prevents further increment.
Related concept
Read the scenario before looking for a memorised answer.
✗
5
Why it's wrong here
Incorrect; the loop exits early.
✗
Compilation error
Why it's wrong here
Incorrect; the code compiles.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates often miscount loop iterations by including the iteration where `break` occurs, forgetting that `break` exits before the loop body's remaining statements (including `count++`) execute.
Detailed technical explanation
How to think about this question
The `break` statement in Java immediately exits the innermost enclosing loop, skipping any remaining code in the current iteration. In this case, when `i` becomes 3, the `if` condition is true, so `break` is executed before `count++` runs for that iteration. The loop's increment expression `++i` is evaluated at the end of each iteration, but `break` bypasses that for the iteration where it fires. This behavior is defined in JLS §14.15. Understanding this is crucial for debugging loops with early exit conditions, such as searching for a value in an array.
KKey Concepts to Remember
Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.
TExam Day Tips
→Watch for words such as best, first, most likely and least administrative effort.
→Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A small business has 20 workstations on the 192.168.1.0/24 network and one public IP from its ISP. The router uses PAT (NAT overload) so all 20 devices share one public address using different source ports. NAT questions test whether you understand the four address terms and which direction each translation applies.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Controlling Program Flow — This question tests Controlling Program Flow — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: 3 — The code uses a `for` loop with `int i = 0; i < 5; ++i`. The loop increments `i` before each iteration check, but the initial value is 0. The loop runs while `i < 5`, so it iterates for `i = 0, 1, 2, 3, 4` — five iterations. However, the loop body contains `if (i == 3) break;`, which terminates the loop when `i` equals 3. At that point, the loop has executed for `i = 0, 1, 2` (three iterations), so `count` is incremented three times, resulting in output 3.
What should I do if I get this 1Z0-829 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Question Discussion
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