- A
Case values can be variables that are not final.
Why wrong: Case values must be compile-time constants.
- B
It can be used with String objects.
String is allowed in switch since Java 7.
- C
It requires a default case.
Why wrong: Default is optional.
- D
It can be used as an expression that yields a value.
Switch expressions were introduced in Java 14.
- E
Each case must have a unique code block.
Why wrong: Multiple case labels can share a code block.
Quick Answer
The correct choices are that the switch statement supports String objects and can be used as an expression that yields a value. Since Java 7, the switch statement has allowed String comparison by internally using the string's hashCode() method to select a case and then verifying equality with the equals() method, making it both efficient and type-safe for textual branching. Additionally, Java 14 introduced switch expressions with arrow syntax, enabling the switch to directly produce a value that can be assigned to a variable or returned, which is a key feature tested on the Oracle Certified Professional Java SE 17 Developer 1Z0-829 exam. A common trap is forgetting that the default case is optional in both statements and expressions, but when used in an expression, it must cover all possible values to avoid a compilation error. Memory tip: think "hash equals arrow" — String uses hashCode and equals, and arrow syntax yields a value.
1Z0-829 Controlling Program Flow Practice Question
This 1Z0-829 practice question tests your understanding of controlling program flow. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Which TWO statements are true about the switch statement in Java?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
It can be used with String objects.
Option B is correct because Java's switch statement supports String objects since Java 7, allowing comparison based on the string's hashCode() and equals() methods. Option D is correct because switch can be used as an expression (e.g., with the arrow syntax) that yields a value, which can be assigned to a variable or returned.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Case values can be variables that are not final.
Why it's wrong here
Case values must be compile-time constants.
- ✓
It can be used with String objects.
Why this is correct
String is allowed in switch since Java 7.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
It requires a default case.
Why it's wrong here
Default is optional.
- ✓
It can be used as an expression that yields a value.
Why this is correct
Switch expressions were introduced in Java 14.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
Each case must have a unique code block.
Why it's wrong here
Multiple case labels can share a code block.
Common exam traps
Common exam trap: answer the scenario, not the keyword
Oracle often tests the misconception that case values can be any variable, but the trap here is that they must be compile-time constants (final or literals), and that switch expressions require exhaustiveness, not a default case.
Detailed technical explanation
How to think about this question
Under the hood, switch on String uses the string's hash code to select a case, then calls equals() to confirm the match, which can have performance implications compared to integer switches. Switch expressions (introduced in Java 14) use the arrow syntax or yield keyword to produce a value, and they must be exhaustive (cover all possible values) when used with enums or sealed classes. A common subtlety is that fall-through in traditional switch statements can lead to unintended execution if break is omitted, but switch expressions avoid this by design.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
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Controlling Program Flow — study guide chapter
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FAQ
Questions learners often ask
What does this 1Z0-829 question test?
Controlling Program Flow — This question tests Controlling Program Flow — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: It can be used with String objects. — Option B is correct because Java's switch statement supports String objects since Java 7, allowing comparison based on the string's hashCode() and equals() methods. Option D is correct because switch can be used as an expression (e.g., with the arrow syntax) that yields a value, which can be assigned to a variable or returned.
What should I do if I get this 1Z0-829 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
About these practice questions
Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
Same concept, more angles
2 more ways this is tested on 1Z0-829
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. Which TWO statements about the switch statement in Java are correct?
medium- ✓ A.The default case can be placed anywhere within the switch block.
- B.Case values can be runtime expressions.
- C.A break statement is mandatory after each case block.
- D.Case labels can be variables if they are final and assigned a constant expression.
- ✓ E.The switch statement can be used with int, char, String, and enum types.
Why A: Option A is correct because the Java Language Specification allows the default case to appear anywhere within the switch block, not just at the end. The switch statement evaluates the expression and jumps to the matching case label; if no match is found, it jumps to the default label regardless of its position. This flexibility is important for code organization and readability.
Variation 2. Which TWO statements about the switch statement in Java are true?
easy- ✓ A.A break statement is optional.
- B.A switch statement can be used as an expression in all cases.
- C.The switch expression can be of type long.
- ✓ D.The switch expression can be of type String.
- E.The case values can be variables.
Why A: Option A is correct because in a Java switch statement, the break statement is optional. If omitted, execution falls through to the next case (fall-through behavior), which can be intentional or lead to bugs. This is a core feature of the switch construct, not a requirement.
Last reviewed: Jun 30, 2026
This 1Z0-829 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-829 exam.
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