The answer is that no change is needed; the code compiles and runs as expected. This is correct because the switch expression with enum types is syntactically valid and complete, using arrow syntax to map each enum constant—NEW, PROCESSING, SHIPPED, and DELIVERED—to its corresponding message, while the default clause ensures that any unexpected status value is handled, making the switch expression exhaustive. On the Oracle Certified Professional Java SE 17 Developer 1Z0-829 exam, this question tests your understanding that switch expressions must cover all possible values, and while enum constants are finite, including a default clause is a safe practice that satisfies the compiler even if the enum is later extended. A common trap is thinking you must omit the default when all enum constants are listed, but the default is optional and does not cause a compilation error. Memory tip: “Default is your safety net—it never breaks a switch expression, only catches what you forget.”
1Z0-829 Controlling Program Flow Practice Question
This 1Z0-829 practice question tests your understanding of controlling program flow. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
A Java application processes a list of orders. Each order has a status: NEW, PROCESSING, SHIPPED, or DELIVERED. The code must print a message based on the status:
- If NEW: "Order received"
- If PROCESSING: "Order in progress"
- If SHIPPED: "Order shipped"
- If DELIVERED: "Order delivered"
- For any other status: "Unknown status"
The developer writes the following code using a switch expression:
String message = switch (status) {
case NEW -> "Order received";
case PROCESSING -> "Order in progress";
case SHIPPED -> "Order shipped";
case DELIVERED -> "Order delivered";
default -> "Unknown status";
};
System.out.println(message);
What is the correct course of action to ensure the code compiles and runs correctly?
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
No change needed; the code compiles and runs as expected.
Option C is correct because the switch expression shown is syntactically valid and complete. It uses the arrow syntax with all enum constants covered and includes a default branch to handle any other status, so it compiles and runs as expected. Switch expressions can yield values and work with enum types, making the code correct as written.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
✗
Add a default branch to handle any other status.
Why it's wrong here
There is already a default branch.
✗
Use if-else if statements because switch cannot be used with enum types.
Why it's wrong here
Switch can be used with enums.
✓
No change needed; the code compiles and runs as expected.
Why this is correct
The code is syntactically correct and covers all cases.
Related concept
Read the scenario before looking for a memorised answer.
✗
Change the switch expression to a switch statement because switch expressions cannot yield values.
Why it's wrong here
Switch expressions can yield values.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates may think switch expressions cannot yield values or that enum types require if-else, but Java's enhanced switch fully supports both, and the default branch is already present, so no change is needed.
Detailed technical explanation
How to think about this question
Switch expressions in Java 14+ can yield values using either arrow syntax (->) or colon syntax with yield. When using enum constants in a switch expression, the compiler checks exhaustiveness; if all enum constants are covered, the default branch is optional, but including it is safe and handles any future enum additions. Under the hood, the switch expression is compiled to a tableswitch or lookupswitch bytecode instruction, and the result is assigned to the variable.
KKey Concepts to Remember
Read the scenario before looking for a memorised answer.
Find the constraint that changes the correct option.
Eliminate answers that are true in general but not in this case.
TExam Day Tips
→Watch for words such as best, first, most likely and least administrative effort.
→Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Controlling Program Flow — This question tests Controlling Program Flow — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: No change needed; the code compiles and runs as expected. — Option C is correct because the switch expression shown is syntactically valid and complete. It uses the arrow syntax with all enum constants covered and includes a default branch to handle any other status, so it compiles and runs as expected. Switch expressions can yield values and work with enum types, making the code correct as written.
What should I do if I get this 1Z0-829 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Question Discussion
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