Question 465 of 509
Working with Streams and Lambda ExpressionshardMultiple ChoiceObjective-mapped

Quick Answer

The answer is to use `.min(Comparator.naturalOrder())` instead of `.sorted().findFirst()`. This is correct because `min()` is a short-circuiting terminal operation that finds the minimum element by traversing the stream once, maintaining only the current smallest value, whereas `sorted()` is a stateful intermediate operation that must sort the entire stream before `findFirst()` can retrieve the first element—an O(n log n) process that wastes time and memory on irrelevant data. On the Oracle Certified Professional Java SE 17 Developer 1Z0-829 exam, this question tests your understanding of stream performance and the distinction between stateful and short-circuiting operations; a common trap is assuming `sorted().findFirst()` is efficient because it reads like a simple “get the smallest” command. Remember the memory tip: “Sort all to find one? No—min finds the minimum in one pass.”

1Z0-829 Working with Streams and Lambda Expressions Practice Question

This 1Z0-829 practice question tests your understanding of working with streams and lambda expressions. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

A stream pipeline filters strings, sorts them, and returns the first match: .filter(s -> s.length() > 3).sorted().findFirst(). This is inefficient because sorted() processes all elements. Which alternative achieves the same result with better performance?

Clue words in this question

Noticing these words before you look at the options changes how you read each choice.

  • Clue: "first"

    Why it matters: Order matters here. You are being tested on which action comes before the others — not which action is generally useful.

Question 1hardmultiple choice
Read the full NAT/PAT explanation →

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

.filter(s -> s.length() > 3).min(Comparator.naturalOrder())

Using min() is a short-circuiting terminal operation that finds the minimum without sorting the entire stream, thus improving performance.

Key principle: NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • .filter(s -> s.length() > 3).min(Comparator.naturalOrder())

    Why this is correct

    min() uses a reduction that processes each element once, maintaining the minimum without sorting.

    Clue confirmation

    The clue word "first" in the question point toward this answer.

    Related concept

    Static NAT maps one inside address to one outside address.

  • .filter(s -> s.length() > 3).sorted().limit(1).findFirst()

    Why it's wrong here

    limit(1) after sorted() does not prevent sorting all elements; sorted() still requires the full sorted order.

  • .filter(s -> s.length() > 3).parallel().sorted().findFirst()

    Why it's wrong here

    parallel does not fix the sorting overhead; sorted() still requires a full sort in parallel, which may not be beneficial.

  • .filter(s -> s.length() > 3).sorted().collect(Collectors.toList()).get(0)

    Why it's wrong here

    Still sorts all elements, and collect triggers full processing.

Common exam traps

Common exam trap: NAT rules depend on direction and matching traffic

NAT is not only about the public address. The inside/outside interface roles and the ACL or rule that matches traffic are just as important.

Detailed technical explanation

How to think about this question

NAT questions usually test address translation, overload/PAT behaviour, static mappings and whether the right traffic is being translated. Read the interface direction and address terms carefully.

KKey Concepts to Remember

  • Static NAT maps one inside address to one outside address.
  • PAT allows many inside hosts to share one public address using ports.
  • Inside local and inside global describe the private and translated addresses.
  • NAT ACLs identify traffic for translation, not always security filtering.

TExam Day Tips

  • Identify inside and outside interfaces first.
  • Check whether the scenario needs static NAT, dynamic NAT or PAT.
  • Do not confuse NAT matching ACLs with normal packet-filtering intent.

Key takeaway

NAT direction and interface roles matter as much as the IP address mapping. Inside/outside designation controls which traffic is translated.

Real-world example

How this comes up in practice

A small business has 20 workstations on the 192.168.1.0/24 network and one public IP from its ISP. The router uses PAT (NAT overload) so all 20 devices share one public address using different source ports. NAT questions test whether you understand the four address terms and which direction each translation applies.

What to study next

Got this wrong? Here's your next step.

Review the four NAT address types (inside local, inside global, outside local, outside global), PAT port overload, and static vs dynamic NAT use cases. Then practise related 1Z0-829 NAT questions on configuration and troubleshooting.

Related practice questions

Related 1Z0-829 practice-question pages

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FAQ

Questions learners often ask

What does this 1Z0-829 question test?

Working with Streams and Lambda Expressions — This question tests Working with Streams and Lambda Expressions — Static NAT maps one inside address to one outside address..

What is the correct answer to this question?

The correct answer is: .filter(s -> s.length() > 3).min(Comparator.naturalOrder()) — Using min() is a short-circuiting terminal operation that finds the minimum without sorting the entire stream, thus improving performance.

What should I do if I get this 1Z0-829 question wrong?

Review the four NAT address types (inside local, inside global, outside local, outside global), PAT port overload, and static vs dynamic NAT use cases. Then practise related 1Z0-829 NAT questions on configuration and troubleshooting.

Are there clue words in this question I should notice?

Yes — watch for: "first". Order matters here. You are being tested on which action comes before the others — not which action is generally useful.

What is the key concept behind this question?

Static NAT maps one inside address to one outside address.

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Last reviewed: Jun 24, 2026

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