Quick Answer
The answer is 0-0 0-1 0-2 1-0 because the labeled break statement in nested loops exits the outer loop entirely when the condition i == 1 && j == 1 is met, rather than breaking only the inner loop. This is a core concept of labeled break in Java, which allows you to terminate an outer loop from within a nested inner loop by specifying the label name after the break keyword. On the Oracle Certified Professional Java SE 17 Developer 1Z0-829 exam, this question tests your understanding of control flow with labels, a common topic in the "Controlling Program Flow" section. A frequent trap is assuming a plain break would stop only the inner loop, but with a label, execution jumps directly out of the labeled block, skipping all remaining iterations. Memory tip: think of the label as a "target exit door"—when you break to it, you leave the entire labeled loop, not just the room you are in.
This 1Z0-829 practice question tests your understanding of controlling program flow. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Given the following code snippet:
```java outer:
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
if (i == 1 && j == 1) {break outer;
}
System.out.print(i + "-" + j + " ");
} }
```
What is the output?
0-0 0-1 0-2 1-0 1-1 1-2
Why wrong: The outer loop is broken, so inner loop stops entirely.
0-0 0-1 0-2 1-0
Correct. The loop prints all combinations until the break condition at (1,1).
0-0 0-1 0-2 1-0 2-0 2-1 2-2
Why wrong: The break exits outer loop, so i never reaches 2.
0-0 0-1 0-2 1-0 1-1
Why wrong: The break occurs before printing (1,1).
Answer choices
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
0-0 0-1 0-2 1-0
The correct answer is B because the labeled `break outer;` statement exits the outer loop entirely when `i == 1` and `j == 1`. Before that condition is met, the inner loop prints pairs for `i=0` (all j values 0,1,2) and for `i=1` with `j=0`. When `i=1` and `j=1`, the break occurs, so `1-1` is never printed, and the outer loop stops, preventing any further iterations.
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
For each option: why learners choose it and why it is or isn't the right answer here.
0-0 0-1 0-2 1-0 1-1 1-2
Why it's wrong here
The outer loop is broken, so inner loop stops entirely.
0-0 0-1 0-2 1-0
Why this is correct
Correct. The loop prints all combinations until the break condition at (1,1).
Related concept
Read the scenario before looking for a memorised answer.
0-0 0-1 0-2 1-0 2-0 2-1 2-2
Why it's wrong here
The break exits outer loop, so i never reaches 2.
0-0 0-1 0-2 1-0 1-1
Why it's wrong here
The break occurs before printing (1,1).
Common exam traps
The trap here is that candidates often forget that a labeled break exits the outer loop entirely, not just the inner loop, leading them to choose option A or D which include `1-1` or later iterations.
Detailed technical explanation
In Java, a labeled break statement terminates the outer loop specified by the label, not just the innermost loop. This is useful for breaking out of nested loops when a specific condition is met, such as searching a 2D array and stopping once a target is found. Without the label, a plain `break` would only exit the inner loop, continuing with the next iteration of the outer loop.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
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FAQ
Controlling Program Flow — This question tests Controlling Program Flow — Read the scenario before looking for a memorised answer..
The correct answer is: 0-0 0-1 0-2 1-0 — The correct answer is B because the labeled `break outer;` statement exits the outer loop entirely when `i == 1` and `j == 1`. Before that condition is met, the inner loop prints pairs for `i=0` (all j values 0,1,2) and for `i=1` with `j=0`. When `i=1` and `j=1`, the break occurs, so `1-1` is never printed, and the outer loop stops, preventing any further iterations.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
Read the scenario before looking for a memorised answer.
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Last reviewed: Jun 25, 2026
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