1Z0-829 Controlling Program Flow Practice Question
Given: int i=0; outer: while(i<3) { for(int j=0; j<3; j++) { if(j==1) break outer; } i++; } What is the value of i after the outer loop?
⚠ Common exam trap
The trap here is that candidates often overlook that `i++` is never reached because the labeled break exits the outer loop before the increment executes, leading them to incorrectly assume `i` is 1 or higher.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
0
(0) because the `break outer` statement immediately terminates the outer `while` loop when `j` equals 1 during the first iteration of the inner `for` loop. Since `i` is incremented only after the inner loop completes, and the inner loop never finishes its first iteration, `i` remains 0.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
1
Why it's wrong here
Incorrect; i++ is not executed because the outer loop is broken.
- ✗
2
Why it's wrong here
Incorrect; i never increments.
- ✗
3
Why it's wrong here
Incorrect; the outer loop does not complete.
- ✓
0
Why this is correct
Correct: i is still 0 when break outer executes.
Go deeper
Related to this question
About these practice questions
Courseiva writes every 1Z0-829 question from scratch — 513 in total, each with an explanation and a wrong-answer breakdown. None are copied from real exams or dumps. Learn why practice questions differ from exam dumps →
JA
Written by Johnson Ajibi, MSc IT Security
Senior Network & Security Engineer · founder of Courseiva
This 1Z0-829 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-829 exam.