Controlling Program Flow →easyMultiple ChoiceObjective-mapped

1Z0-829 Controlling Program Flow Practice Question

Given: for(int i=0; i<3; i++) { for(int j=0; j<3; j++) { if(i==1 && j==1) break; } } What is the value of i after the outer loop completes?

⚠ Common exam trap

The trap here is that candidates often mistakenly think `break` exits all nested loops or that the loop variable retains the value at the time of the break, leading them to choose 1 or 2 instead of recognizing the outer loop continues to completion.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

The outer loop variable `i` increments from 0 to 2. When `i` is 1 and `j` is 1, the `break` statement exits only the inner `for` loop, not the outer loop. The outer loop continues to its next iteration, incrementing `i` to 2, then to 3. When `i` becomes 3, the outer loop condition `i < 3` fails, so the loop terminates. Thus, after the outer loop completes, `i` is 3.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
1
Why it's wrong here
Incorrect; the outer loop does not stop at i=1.
✗
2
Why it's wrong here
Incorrect; the outer loop continues to i=3.
✗
4
Why it's wrong here
Incorrect; i never reaches 4 because the loop condition i<3 stops at i=3.
✓
3
Why this is correct
Correct: the outer loop completes all three iterations, ending with i=3.

Go deeper

1Z0-829 Controlling Program Flow Practice Question

Why each option matters

Option-by-option breakdown

Related to this question