1Z0-829 do-while loop Practice Question
Consider the following do-while loop:
```java
int x = 10;
do { x--;
} while (x < 10);
System.out.println(x); ```
What is printed?
⚠ Common exam trap
Candidates often assume that the loop will eventually stop when x reaches some value, but the condition x < 10 is always true after the first iteration because x is decreasing from 10. This leads to an infinite loop. For OCP, always trace the loop carefully, especially when the condition compares a decreasing variable to a constant.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
3
The do-while loop executes the body first (x--), then checks the condition x < 10. After the first iteration, x becomes 9, and the condition (9 < 10) is true. As x continues to decrease, it will always be less than 10, so the condition remains true forever. This results in an infinite loop; the program never reaches the print statement. Therefore, no output is produced, and none of the options (3, 2, 1) are correct.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✓
3
Why this is correct
Incorrect. The loop does not terminate, so no value is printed. This answer mistakenly assumes the loop stops when x becomes 3.
- ✗
The loop does not compile because x is not declared final.
Why it's wrong here
Incorrect. The variable x does not need to be final; the code compiles. The loop runs indefinitely.
- ✗
2
Why it's wrong here
Incorrect. The loop never terminates, so 2 is never printed.
- ✗
1
Why it's wrong here
Incorrect. The loop never terminates, so 1 is never printed.
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