Question 445 of 513
1Z0-829 Handling Exceptions Practice Question
Consider the following code:
public void process() throws Exception {try { riskyMethod();
} catch (IOException | SQLException e) {throw e;
} }
Assuming riskyMethod() declares both IOException and SQLException, what is the result?
⚠ Common exam trap
The trap here is that candidates mistakenly believe multi-catch variables cannot be rethrown without a cast, confusing them with pre-Java 7 single-catch blocks where the variable was not effectively final.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
The code compiles and runs correctly.
In Java 7+, multi-catch variables are implicitly final, so they can be rethrown without a cast. The compiler knows that the thrown exception is exactly one of the caught types (IOException or SQLException), and since both are checked exceptions declared in the method signature, the code compiles and runs correctly. Option D is correct.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Compilation fails because you cannot rethrow a multi-catch variable.
Why it's wrong here
Rethrow is allowed with multi-catch.
- ✗
Compilation fails because the catch variable must be cast to Exception.
Why it's wrong here
No cast needed.
- ✗
The code compiles, but throws a ClassCastException at runtime.
Why it's wrong here
No runtime error.
- ✓
The code compiles and runs correctly.
Why this is correct
Works fine in Java 17.
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Last reviewed: Jun 25, 2026
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