Question 502 of 513
1Z0-829 Controlling Program Flow Practice Question
Consider the following code:
```java boolean a = true, b = false, c = false;
if (a && b || c) {System.out.println("True");
} else {System.out.println("False");
}
```
What is the output?
⚠ Common exam trap
The trap here is that candidates often misinterpret the expression as `a && (b || c)` due to left-to-right reading, forgetting that `&&` has higher precedence than `||` in Java.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
False
The expression `a && b || c` evaluates as `(a && b) || c` due to operator precedence (`&&` has higher precedence than `||`). With `a=true`, `b=false`, `c=false`, `(true && false)` is `false`, then `false || false` is `false`, so the `else` branch prints "False". Option B is correct.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
The code does not compile because of invalid boolean expression.
Why it's wrong here
The expression is valid.
- ✓
False
Why this is correct
Correct. a&&b is false, then false||c is false.
- ✗
The output cannot be determined without runtime values.
Why it's wrong here
All values are known at compile time.
- ✗
True
Why it's wrong here
The expression evaluates to false because precedence groups && before ||.
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Last reviewed: Jun 25, 2026
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