Controlling Program Flow →easyMultiple ChoiceObjective-mapped

1Z0-829 Controlling Program Flow Practice Question

Consider the following code:

```java boolean a = true, b = false, c = false;

if (a && b || c) {

System.out.println("True");

} else {

System.out.println("False");

```

What is the output?

⚠ Common exam trap

The trap here is that candidates often misinterpret the expression as `a && (b || c)` due to left-to-right reading, forgetting that `&&` has higher precedence than `||` in Java.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

✓

False

The expression `a && b || c` evaluates as `(a && b) || c` due to operator precedence (`&&` has higher precedence than `||`). With `a=true`, `b=false`, `c=false`, `(true && false)` is `false`, then `false || false` is `false`, so the `else` branch prints "False". Option B is correct.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

✗
The code does not compile because of invalid boolean expression.
Why it's wrong here
The expression is valid.
✓
False
Why this is correct
Correct. a&&b is false, then false||c is false.
✗
The output cannot be determined without runtime values.
Why it's wrong here
All values are known at compile time.
✗
True
Why it's wrong here
The expression evaluates to false because precedence groups && before ||.

Go deeper

1Z0-829 Controlling Program Flow Practice Question

Why each option matters

Option-by-option breakdown

Related to this question