Question 1easymultiple choice
Full question →- A
[A, D]
Why wrong: set changed index 0 to C.
- B
[C, D]
Both modifications affect the list.
- C
[A, B]
Why wrong: Changes are applied.
- D
[C, B]
Why wrong: Array modification changes list element too.
Question 369 of 509
Quick Answer
The correct answer is [C, D] because the `Arrays.asList()` method returns a fixed-size list backed by the original array, meaning the list and the array share the same underlying data. When you call `list.set(0, "C")`, it directly modifies the first element of the backing array, and when you later assign `array[1] = "D"`, that change is immediately visible through the list. This concept is frequently tested on the Oracle Certified Professional Java SE 17 Developer 1Z0-829 exam, often as a trick to see if you remember that while the list’s size is fixed, its elements remain mutable and synchronized with the array. A common trap is assuming `Arrays.asList` creates an independent copy, but it does not—any structural modification like `add` or `remove` throws `UnsupportedOperationException`. Memory tip: think of `Arrays.asList` as a live window into the array, not a snapshot—what you change in one, you see in the other.
1Z0-829 Working with Arrays and Collections Practice Question
This 1Z0-829 practice question tests your understanding of working with arrays and collections. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.
Given: String[] array = {"A", "B"}; List<String> list = Arrays.asList(array); list.set(0, "C"); array[1] = "D"; What is the content of the list?
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
[C, D]
Option B is correct because `Arrays.asList()` returns a fixed-size list backed by the original array. Modifications to the list via `set()` directly affect the backing array, and modifications to the array elements are reflected in the list. After `list.set(0, "C")`, the first element of both the list and the array becomes "C". After `array[1] = "D"`, the second element of both becomes "D". Thus the list content is [C, D].
Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
[A, D]
Why it's wrong here
set changed index 0 to C.
- ✓
[C, D]
Why this is correct
Both modifications affect the list.
Related concept
Read the scenario before looking for a memorised answer.
- ✗
[A, B]
Why it's wrong here
Changes are applied.
- ✗
[C, B]
Why it's wrong here
Array modification changes list element too.
Common exam traps
Common exam trap: answer the scenario, not the keyword
The trap here is that candidates often forget that `Arrays.asList()` returns a list backed by the original array, so modifications through either reference are reflected in both, leading them to choose options that reflect only one of the two changes.
Detailed technical explanation
How to think about this question
`Arrays.asList()` returns a `java.util.Arrays$ArrayList` (not `java.util.ArrayList`), which is a fixed-size list backed by the original array. Any structural modification (like `add` or `remove`) throws `UnsupportedOperationException`, but `set()` is allowed and directly writes to the backing array. This bidirectional visibility is a key behavior: changes via the list or the array are immediately visible through the other reference. In real-world scenarios, this is useful for creating a list view of an array without copying data, but it can lead to subtle bugs if developers assume the list is independent.
KKey Concepts to Remember
- Read the scenario before looking for a memorised answer.
- Find the constraint that changes the correct option.
- Eliminate answers that are true in general but not in this case.
TExam Day Tips
- Watch for words such as best, first, most likely and least administrative effort.
- Review why wrong options are wrong, not only why the correct option is correct.
Key takeaway
Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.
Real-world example
How this comes up in practice
A practitioner preparing for the 1Z0-829 exam encounters this exact type of scenario on the job. The correct answer here is not the most general option — it is the best answer for the specific constraint described. Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option. Real exam questions reward reading the full scenario before eliminating options, because the constraint defines which answer fits.
What to study next
Got this wrong? Here's your next step.
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
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Working with Arrays and Collections — study guide chapter
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FAQ
Questions learners often ask
What does this 1Z0-829 question test?
Working with Arrays and Collections — This question tests Working with Arrays and Collections — Read the scenario before looking for a memorised answer..
What is the correct answer to this question?
The correct answer is: [C, D] — Option B is correct because `Arrays.asList()` returns a fixed-size list backed by the original array. Modifications to the list via `set()` directly affect the backing array, and modifications to the array elements are reflected in the list. After `list.set(0, "C")`, the first element of both the list and the array becomes "C". After `array[1] = "D"`, the second element of both becomes "D". Thus the list content is [C, D].
What should I do if I get this 1Z0-829 question wrong?
Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.
What is the key concept behind this question?
Read the scenario before looking for a memorised answer.
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Courseiva creates original exam-style practice questions with explanations and wrong-answer analysis. It does not publish real exam questions, exam dumps, or protected exam content. Learn why practice questions differ from exam dumps →
Same concept, more angles
1 more ways this is tested on 1Z0-829
These questions test the same concept from different angles. Work through them to make sure you can recognise it however the exam phrases it.
Variation 1. Which of the following correctly converts an array of strings to a List?
easy- A.Collections.toList(array) converts the array.
- B.List.of(array) returns a mutable list.
- ✓ C.Arrays.asList(array) returns a fixed-size list backed by the array.
- D.Arrays.asList(array) returns a new ArrayList with a copy of the elements.
Why C: Option C is correct because `Arrays.asList(array)` returns a fixed-size list backed by the original array, meaning changes to the list (like `set`) reflect in the array, but structural modifications (like `add` or `remove`) throw `UnsupportedOperationException`. This is the standard, exam-relevant way to convert an array to a List in Java.
Last reviewed: Jun 25, 2026
This 1Z0-829 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-829 exam.
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