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Java I/O API and Securing ApplicationseasyMultiple ChoiceObjective-mapped

1Z0-829 Java I/O API and Securing Applications Practice Question

A developer needs to read a large text file (several gigabytes) line by line as efficiently as possible, processing each line without loading the entire file into memory. Which approach should the developer use?

⚠ Common exam trap

It's easy for candidates to choose `BufferedReader` (Option A) because it is familiar, but they overlook that `Files.lines` is the modern, stream-based API that is both more idiomatic and safer for large files, and that `Files.readAllLines` (Option C) is a common pitfall for memory exhaustion.

Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

Use Files.lines with a try-with-resources block, and process each line using the stream.

`Files.lines` returns a `Stream<String>` that lazily reads lines from the file, processing them one at a time without loading the entire file into memory. The try-with-resources block ensures the underlying file handle is closed automatically, preventing resource leaks. This approach is specifically designed for efficient, memory-safe line-by-line processing of large files.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • Use a FileReader wrapped in a BufferedReader, and process each line in a loop.

    Why it's wrong here

    Although it reads line by line, it requires manual handling of the resource closure to avoid leaks. The approach is correct but less concise than using Files.lines with try-with-resources.

  • Use a FileInputStream to read bytes, then manually parse newline characters.

    Why it's wrong here

    FileInputStream reads raw bytes, requiring low-level parsing, which is more error-prone and less efficient for line-oriented processing.

  • Use Files.readAllLines to read the entire file into a List<String> and then iterate.

    Why it's wrong here

    Files.readAllLines loads the entire file into memory, which would cause OutOfMemoryError for a large file.

  • Use Files.lines with a try-with-resources block, and process each line using the stream.

    Why this is correct

    Files.lines returns a Stream that reads lines lazily, and try-with-resources ensures the underlying file handle is closed automatically. This is the most efficient and idiomatic solution.

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Written by Johnson Ajibi, MSc IT Security

Senior Network & Security Engineer · founder of Courseiva

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