Question 50 of 513
1Z0-829 Controlling Program Flow Practice Question
A developer is implementing a method that processes a collection of objects. The objects are instances of various classes that implement a common interface. The developer wants to use a switch expression to perform different actions based on the runtime type of each object. Which approach is correct?
⚠ Common exam trap
Many exam-takers assume a default case is always required in switch expressions, but the exam tests the knowledge that pattern matching with sealed types or exhaustive coverage can omit the default case, and that including one may actually mask missing cases and defeat compile-time safety.
Answer choices
Why each option matters
Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.
Correct answer & explanation
✓
Use a switch expression with pattern matching without a default case if all possible types are covered.
Java 17+ switch expressions with pattern matching allow exhaustive type coverage without a default case when all possible subtypes of the sealed interface or hierarchy are explicitly listed. This ensures compile-time safety and eliminates the need for a default branch, aligning with the principle of exhaustive pattern matching.
Answer analysis
Option-by-option breakdown
For each option: why learners choose it and why it is or isn't the right answer here.
- ✗
Use a series of if-else statements with instanceof.
Why it's wrong here
if-else statements are less readable and do not leverage switch expressions.
- ✗
Use a switch expression with pattern matching and a default case.
Why it's wrong here
A default case is not required if all types are covered; it may cause unintended behavior if not carefully handled.
- ✗
Use a traditional switch statement with instanceof checks and casting.
Why it's wrong here
Traditional switch statement works but is not the best practice for switch expressions.
- ✓
Use a switch expression with pattern matching without a default case if all possible types are covered.
Why this is correct
Switch expressions must be exhaustive; if all subtypes are covered, no default is needed.
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Last reviewed: Jun 25, 2026
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