Question 193 of 509
Controlling Program FloweasyMultiple ChoiceObjective-mapped

Quick Answer

The correct choice is the enhanced for loop with a break statement, as in for(int i : array) { if(i == -1) break; }. This works because the break keyword immediately terminates the innermost loop when the condition is met, halting all further iteration through the array. On the Oracle Certified Professional Java SE 17 Developer 1Z0-829 exam, this question tests your understanding of loop control flow and the precise behavior of break—specifically that it exits only the current loop, not any outer loops. A common trap is confusing break with continue, which skips only the current iteration rather than ending the loop entirely. Remember that break is your "emergency exit" for loops: once the sentinel value -1 appears, break slams the door shut on the entire loop. For a quick memory tip, think of break as a "brick wall" that stops all forward movement in the loop.

1Z0-829 Controlling Program Flow Practice Question

This 1Z0-829 practice question tests your understanding of controlling program flow. Read the scenario carefully and evaluate each option against the stated constraints before committing to an answer. After answering, compare your reasoning against the explanation and wrong-answer breakdown below. Once you have made your selection, read the full explanation to reinforce the concept and understand why each distractor is designed to mislead on exam day.

A developer is designing a loop to iterate through an array of integers and stop processing when the value -1 is encountered. Which loop construct should be used?

Question 1easymultiple choice
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Answer choices

Why each option matters

Answer the question above first, then reveal the full breakdown to understand why each option is right or wrong.

Correct answer & explanation

for(int i : array) { if(i == -1) break; }

Option C is correct because the `break` statement immediately terminates the loop when the value -1 is encountered, which is exactly what the requirement specifies. In Java, `break` exits the innermost loop or switch statement, making it the appropriate control flow mechanism for stopping iteration upon a condition.

Key principle: Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Answer analysis

Option-by-option breakdown

For each option: why learners choose it and why it is or isn't the right answer here.

  • for(int i : array) { if(i == -1) exit; }

    Why it's wrong here

    There is no exit keyword in Java; this is not valid syntax.

  • for(int i : array) { if(i == -1) return; }

    Why it's wrong here

    The return statement exits the method, which stops the loop but also exits the method, which may not be intended.

  • for(int i : array) { if(i == -1) break; }

    Why this is correct

    The break statement immediately exits the loop, which is the correct way to stop processing upon encountering -1.

    Related concept

    Read the scenario before looking for a memorised answer.

  • for(int i : array) { if(i == -1) continue; }

    Why it's wrong here

    The continue statement skips the current iteration and continues with the next, so the loop does not stop.

Common exam traps

Common exam trap: answer the scenario, not the keyword

The trap here is that candidates often confuse `break` with `continue` or mistakenly use `return` or `exit` to exit a loop, not realizing that `break` is the precise mechanism for loop termination without affecting the rest of the method or JVM.

Trap categories for this question

  • Keyword trap

    There is no exit keyword in Java; this is not valid syntax.

Detailed technical explanation

How to think about this question

The enhanced for-each loop (`for(int i : array)`) iterates over each element sequentially, and `break` works identically in both traditional and enhanced for loops by jumping to the first statement after the loop. A subtle behavior is that if the array contains -1 multiple times, `break` only stops at the first occurrence, which matches the requirement to 'stop processing when the value -1 is encountered.'

KKey Concepts to Remember

  • Read the scenario before looking for a memorised answer.
  • Find the constraint that changes the correct option.
  • Eliminate answers that are true in general but not in this case.

TExam Day Tips

  • Watch for words such as best, first, most likely and least administrative effort.
  • Review why wrong options are wrong, not only why the correct option is correct.

Key takeaway

Answer the scenario, not the keyword: identify the specific constraint before choosing the most familiar-sounding option.

Real-world example

How this comes up in practice

A small business has 20 workstations on the 192.168.1.0/24 network and one public IP from its ISP. The router uses PAT (NAT overload) so all 20 devices share one public address using different source ports. NAT questions test whether you understand the four address terms and which direction each translation applies.

What to study next

Got this wrong? Here's your next step.

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

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FAQ

Questions learners often ask

What does this 1Z0-829 question test?

Controlling Program Flow — This question tests Controlling Program Flow — Read the scenario before looking for a memorised answer..

What is the correct answer to this question?

The correct answer is: for(int i : array) { if(i == -1) break; } — Option C is correct because the `break` statement immediately terminates the loop when the value -1 is encountered, which is exactly what the requirement specifies. In Java, `break` exits the innermost loop or switch statement, making it the appropriate control flow mechanism for stopping iteration upon a condition.

What should I do if I get this 1Z0-829 question wrong?

Identify which exam domain this question belongs to, review the core concept, then practise similar questions from the same domain.

What is the key concept behind this question?

Read the scenario before looking for a memorised answer.

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Last reviewed: Jun 25, 2026

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This 1Z0-829 practice question is part of Courseiva's free Oracle certification practice question bank. Courseiva provides original exam-style practice questions with explanations, topic-based practice, mock exams, readiness tracking, and study analytics to help learners prepare for the 1Z0-829 exam.