1Z0-811 Primitives, Strings and Operators Practice Question

Correct answer & explanation

Options A, C, D are correct. A: byte addition promoted to int, then assigned to byte requires explicit cast? Actually byte + byte = int, but assignment to byte will require explicit cast. Wait: byte b = 1+2? 1 and 2 are literals, compile-time constant, so assignment is allowed because constant expression. Actually 1 and 2 are int literals, but the result is compile-time constant 3, which fits in byte, so it's allowed. So A compiles. B: int + long = long, assigning to int requires explicit cast, so compile error. C: double d = 10; 10 is int, widening assignment to double is fine. D: boolean b = (false || true); boolean expression, fine. E: float f = 5.5; 5.5 is double by default, requires explicit cast or f suffix, so compile error. So correct: A, C, D.